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slava [35]
3 years ago
12

Solve the equation 5(x+2)=6x+3x-14

Mathematics
1 answer:
Lapatulllka [165]3 years ago
5 0

Answer: x = 6

Step-by-step explanation:

First step is to distribute the 5(x + 2).

5x + 10 = 6x + 3x - 14

The 6x and the 3x on the right can be combined.

5x + 10 = 9x - 14

Now add 14 to both sides to isolate the 9x.

5x + 24 = 9x

Subtract 5x from both sides.

24 = 4x

Divide by 4 to get x by itself.

6 = x

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Use the zero product property to find the solitions to the equation(x+2)(x+3)=12.
kykrilka [37]

Answer:

(x + 2) (x + 3) = x² + 3x + 2x + 6 = 12  (multiply the binomials)

(x + 2) (x + 3) = x² + 5x + 6 = 12

(x + 2) (x + 3) = x² + 5x + 6-12 = 0  (add the like term and bring the positive 12 to the other side which makes it negative)

x² + 5x + 6 = 0

Using the snowflake method -  (finding the factors of 6 that adds/subtracts to give you 5).  

This method will give you the factors (x + 6)(x - 1)

ZERO PROPERTY RULE:

(x + 6) = 0

x = -6

(x - 1) = 0

x = 1

The two solutions to the equation are -6 and 1.

7 0
3 years ago
19 is 20%of what number
zloy xaker [14]

Answer:

19 is 20% of 95.

Step-by-step explanation:

6 0
3 years ago
What is 90 divided by 12???? <br> pls help i need to get my grades up
Andrew [12]

Answer:

7.5

Step-by-step explanation:

cant u just  g oogle it?

5 0
3 years ago
Read 2 more answers
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
In the year 2005, a total of 750 fish were introduced into a manmade lake. The fish population was expected to grow at a rate of
tangare [24]
The population of the fish is given by P(t) = 750(1 + 0.083)^t; where t is the number of years after 2005.
Here, t = 2050 - 2005 = 45

Population in 2050 = 750(1.083)^45 = 750(36.16) = 27,123
8 0
3 years ago
Read 2 more answers
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