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lbvjy [14]
2 years ago
8

WHat is the largest multiple of 5 that is less than 24

Mathematics
1 answer:
kolbaska11 [484]2 years ago
8 0

Answer:

20

Step-by-step explanation:

5*4=20

5*5=25, but it is bigger than 24.

So the ans is 20

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Answer:

1. Difference

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Step-by-step explanation:

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for what base-6 digit $d$ is $2dd5 6$ divisible by the base 10 number 11? (here $2dd5 6$ represents a base-6 number whose first
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The digits base is 7 then we should convert them into base 6.

The exponent or power to which a base must be raised to yield a given number. Expressed mathematically, x is the logarithm of n to the base b if bx = n, in which case one writes x = logbn.

Here the conclusion is that there are many bases in the mathematics so what will happen is that we should convert these bases. For example, we have to convert base 10 of a number which is called decimal number can be converted into binary number whose base is 2 and after then if the digits base is 7 then we should convert them into base 6.

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5 0
1 year ago
Just need the answer DAN ONLY
umka21 [38]
The answer is -2
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3 years ago
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In a coordinated plane what is the distance between (-4, 12) and (-4 -1)
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Answer:

(0,13)

Step-by-step explanation:

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3 years ago
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jessie has some nickels, dimes, and quarters in her bank. The number of coins is 31. The expression 0.05n + 0.10d +0.24q represe
AVprozaik [17]

Given expression for all coins is 0.05n + 0.10d +0.25q .

Total value of all coins = $3.25.

Therefore,

0.05n + 0.10d +0.25q = 3.25 ------------------(1)

Total number of coins = 31.

We can setup second equation as

n+d+q = 31.  -----------------------(2).

Jessie has four more dimes than she does quarters.

Number of quarters = q.

Number of dimes is four more than number of quarter.

Therefore,

d = q + 4. ------------------------(3)

Substituting d=q+4 in first and second equation we get

0.05n + 0.10(q+4) +0.25q = 3.25 => 0.05n +0.10q + 0.40 +0.25q = 3.25

0.05n +0.35q = 3.25 - 0.40

0.05n +0.35q = 2.85. ------------------------(4)

n+d+q = 31  => n+ q+4 +q = 31.

n+2q  =31 -4

n+2q = 27.    ------------------------(5

Solving equation (5) for n

n = 27-2q.

Substituting n = 27-2q in (4) equation, we get

0.05(27-2q)  +0.35q = 2.85

1.35 - 0.10q +0.35q = 2.85

1.35 +0.25q = 2.85

0.25q = 2.85 - 1.35

0.25q = 1.5.

Dividing both sides by 0.25, we get

q = 6.

Plugging q=6 in n = 27-2q, we get

n = 27 -2(6) = 27-12 = 15.

Plugging n=15 and q=6 in second equation n+d+q = 31.

15+d+6 = 31.

21 +d = 31.

Subtracting 21 from both sides, we get

21 +d -21= 31-21

d = 10.

<h3>Therefore, number of dimes = 10, number of quarters = 6 and number of nickels = 15.</h3>
7 0
2 years ago
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