The number of situps form an AP with first term (a) = 17 and common difference (d) = 4
Tn = a + (n - 1)d
T12 = 17 + (12 - 1) x 4 = 17 + 11(4) = 17 + 44 = 61
Therefore, she will do 61 situps on day 12.
I think it might be 15n + 12 sorry if it’s not
Um 3 times 3/8 = 1.125
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Answer:
67.5 tiles
Step-by-step explanation: 18 times 15 equals 270, and 270 divided by 4 equals 67.5. So it will take 67.5 4in tiles to cover the room.
The information we've been given is:
12 heads
15 tails
From those, we find that there are 12 + 15 = 27 coins.
Let's examine these ratios as such:
- 12 heads to 27 coins -
There are indeed 12 heads and 27 coins, so this comparison agrees with our data.
- 15 tails to 12 heads -
Again, nothing here contradicts with our data, so this would be correct as well
- 12 heads to 15 tails -
Simply a reversed version of the ratio above; still a completely valid way to compare the relative quantities of heads and tails
- 5 tails to 9 coins -
This one needs a little more examination. We observe that the ratio of tails to coins with our given data is 15 tails to 27 coins. This seems to go against our data, but we can simplify our ratio by dividing both the number of tails and the number of coins by 3, which indeed gives us the ratio 5 tails to 9 coins.
So, all of the given ratios are correct.
