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3 years ago

Please answer these 3 questions there easy 30 points and brainliest.

Mathematics

1 answer:

irina1246 [14]3 years ago

8 0

Answer:

4) 100 ounces

a) 377.6

b) 7.084

c)1,107.6

d) 680.8

6) 8.9207 percent

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System of equations y >4, and y> |x-1|

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3 years ago

Two Friends have agreed to do a job with pace $2,000 total together there receive apart payment Of 0.25 Of the total amount How

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3 years ago

Help with these two figured and you shall be granted points. Good deal, half off.

STALIN [3.7K]

Answer:

5. C - 180ft²

6. D - 120m³

Step-by-step explanation:

(6.5 x 11) = 71.5

(6 x 2.5) = 15

(6 x 11) = 66

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3 years ago

Is a exponent determined by the amount of zeros in the number?

Alex777 [14]

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3 0

3 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

3 years ago