Answer:
2a
Step-by-step explanation:
-6 and +6 cancel out leaving the 2a by itself.
Answer:
5.5
Step-by-step explanation:
2,3,3,4,5,7,8,8,8,10,10,12
The mean of this data is 7.5. So what you are trying to figure out is the mean between 2 and 7. Since that is 3 and 4 it would be 3.5. So 3.5 is the Q1. Now you have to figure out the mean between 8 and 12. That is 9. This is Q3. You have to subtract 9-3.5 and that is the interquartile range. So 5.5 is the answer. I hope that made sense.
Answer:
(a) |s - x| ≤ 3/16
(b) 4 15/16 ≤ x ≤ 5 5/16
Step-by-step explanation:
(a) The absolute value of the difference from spec must be no greater than than the allowed tolerance:
|s - x| ≤ 3/16
__
(b) Put 5 1/8 for s in the above equation and solve.
|5 1/8 - x| ≤ 3/16
-3/16 ≤ 5 1/8 -x ≤ 3/16
3/16 ≥ x -5 1/8 ≥ -3/16 . . . . multiply by -1 to get positive x
5 5/16 ≥ x ≥ 4 15/16 . . . . . . add 5 1/8
Pieces may be between 4 15/16 and 5 5/16 inches in length.
Answer:
1248' x 2056' so I think you missed copying decimals but I would asume B
Step-by-step explanation:
312''x(1/(1/4''))=1248'
514''x(1'/(1/4''))=2056'
assuming you means k = log_2(3) [as log(2)3 is the same thing as 3log(2) due to multiplication being commutative]
given log(ab) = log(a) + log(b)
log_2(48) = log_2(3) + log_2(16)
