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marissa [1.9K]
3 years ago
6

Write a ratio, in simplest form, that compares the two quantities (show your work): 3 years to 6 months

Mathematics
1 answer:
lutik1710 [3]3 years ago
8 0

Answer:


Step-by-step explanation:

1 year has 375 days so times that by 3 its is 1125.

6 months have 187.5 days or 187 days and 12 hours.

so 1125:187.5 which is 6.

The ratio is 6:1

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Whoops i forgot to read the lesson :P 30 points
andriy [413]

Step-by-step explanation:

I'll do 2.

Alright,Alex let say we have factored a quadratic into two binomial, for example

(5x + 3)(6x - 4)

If we set both of those equal to zero

(5x + 3)(6x + 4) = 0

We can used the zero product property in this case to find the roots of the quadratic equation.

This means that

if  \: ab = 0 \: then \: a = 0 \: and \: b = 0

This means we set each binomal equal to zero to find it root.

5x + 3 = 0

5x =  - 3

x =  -  \frac{3}{5}

6x + 4 = 0

6x =  - 4

x =  -  \frac{2}{3}

So our roots are negative 3/5 and negative 2/3 using zero product property

6 0
2 years ago
Please help will give brainlist
adoni [48]

Answer:

It would be option 2.

Step-by-step explanation:

This is because option 1 does not have a irrational number that goes on indefinitely, option three has the square root of 25, which equals 5 meaning it is rational, and the last option also gives us rational choices. Therefore, the only possibility is that it would be option 2.

6 0
3 years ago
Read 2 more answers
Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
A set X consists of all real numbers greater than or equal to 1. Use set-builder notation to define X.
vitfil [10]

Theory:

The standard form of set-builder notation is <span>
 
{ x | “x satisfies a condition” } </span>

This set-builder notation can be read as “the set of all x such that x (satisfies the condition)”.

For example, { x | x > 0 }  is equivalent to “the set of all x such that x is greater than 0”.

 

Solution:

In the problem, there are 2 conditions that must be satisfied:

<span>1st: x must be a real number</span>

In the notation, this is written as “x ε R”. Where ε means that x is “a member of” and R means “Real number”

 

<span>2nd: x is greater than or equal to 1</span>

This is written as “x ≥ 1”

 

Answer:

Combining the 2 conditions into the set-builder notation:

<span>X = { x | x ε R and x ≥ 1 } </span>
8 0
3 years ago
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Advocard [28]

Answer:

Congruent angles and proportional side lengths

Step-by-step explanation:

4 0
3 years ago
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