F'(x)=-2x{e^(-x²)}
Equating f'(x)=0,
i.e,
-2x{e^(-x²)}=0....eqn(i)
For maximum slope:
Differentiating (i) wrt x,we get,
4x² {e^(-x²)}-2 {e^(-x²)}=0
{e^(-x²)} [4x²-2]=0
4x²-2=0
x=1/√2
If f(x)=y then f'(x)=dy/dx=slope
So,
Maximum slope
= f'(x)
= -2x{e^(-x²)}
=-2×(1/✓2){e^(-1/✓2)²}
= -✓2{e^(-1/2)}
=(-sqrt 2/sqrt e)
=-sqrt(2/e)➡c is correct
Step-by-step explanation:
please sorry to barge into your question without any reasonable answer all I want to say is that this is a graph and I think that the domain and range this is increasing to calculate like the unit for example you have - 9 and - 3 you should calculate how many units are between -9 and -2 I'm not sure and I just really need marks now point where I can get on with my procedure so sorry for just barging in like that I'm so sorry
Answer: 120 minutes.
Step-by-step explanation:
It takes her 75/10 = 7.5 minutes to run 1 mile. If she wants to run 16 miles, it will taker her 7.5 * 16 = 120 minutes.
Answer:
A.
Step-by-step explanation:
4 + 8 = 12 which is < 13.
Answer:
Horizontal line
Step-by-step explanation:
Zero slope means that the quotient "rise/run" equals zero.
A zero for a quotient of two numbers implies that the NUMERATOR is zero and the denominator different from zero.
Analyzing what a "rise" of zero means, we understand that there is NO RISE in the graph of the line. And no rise of any type means the line is flat (horizontal).