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ANEK [815]
3 years ago
5

Plz help 2minutes before class

Mathematics
2 answers:
Crank3 years ago
8 0

Answer:

mon 50.75

tue 47.25

wed 36.05

thur 54.25

fri 36.75

Step-by-step explanation:

I'm not 100% sure if that's right

yarga [219]3 years ago
5 0
Tuesday might be the right answer I’m not 100% sure
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A tourist group arrived at the boat dock for a boat ride in the morning. There were 252 people in the group. Another tourist gro
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Its 15 boats bcuz...252+288=540 and 540/36= 15 boats :D
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The U-Pick farm lets us pick 4 pounds of strawberries for 5 dollars.
Rina8888 [55]

Answer:

$1.25.

Step-by-step explanation:

7 0
3 years ago
Express 0.035 metre into km​
azamat

Answer:

0.000035km

Step-by-step explanation:

1km =1000m \\ x = 0.035m

use \:  \: cross \:  \: multipication

0.035 \times 1 = 1000x \\ 0.035 = 1000x \\  \frac{0.035}{1000}  =  \frac{1000x}{1000}  \\ x = 0.000035km

6 0
3 years ago
Read 2 more answers
Suppose that in a random selection of 100 colored​ candies, 28​% of them are blue. The candy company claims that the percentage
Zigmanuir [339]

Answer:

We conclude that the percentage of blue candies is equal to 29​%.

Step-by-step explanation:

We are given that in a random selection of 100 colored​ candies, 28​% of them are blue. The candy company claims that the percentage of blue candies is equal to 29​%.

Let p = <u><em>population percentage of blue candies</em></u>

So, Null Hypothesis, H_0 : p = 29%     {means that the percentage of blue candies is equal to 29​%}

Alternate Hypothesis, H_A : p \neq 29%     {means that the percentage of blue candies is different from 29​%}

The test statistics that will be used here is <u>One-sample z-test for</u> <u>proportions</u>;

                         T.S.  =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of blue coloured candies = 28%

           n = sample of colored​ candies = 100

So, <u><em>the test statistics</em></u> =  \frac{0.28-0.29}{\sqrt{\frac{0.29(1-0.29)}{100} } }

                                    =  -0.22

The value of the z-test statistics is -0.22.

<u>Also, the P-value of the test statistics is given by;</u>

               P-value = P(Z < -0.22) = 1 - P(Z \leq 0.22)

                            = 1 - 0.5871 = 0.4129

Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of z, <u><em>so we insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the percentage of blue candies is equal to 29​%.

4 0
3 years ago
What is the solution to -|-5 + 2|.
prisoha [69]
Im guessing those are those brackets?
3 0
3 years ago
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