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Leni [432]
3 years ago
10

Solve for x.4(5x-20)=-20

Mathematics
2 answers:
serg [7]3 years ago
6 0

4(5x-20)=-20\\\\20x-80=-20\\\\20x=60\\\\x=3

olasank [31]3 years ago
4 0

Answer:

x=3

Step-by-step explanation:

4(5x-20)=-20

20x-80=-20 (distribute)

20x=60 (add)

x=3 (divide)

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1) x^2=x\cdot x, and x(x+3)=x^2+3x. Subtracting this from the numerator gives a remainder of

(x^2-13x-48)-(x^2+3x)=-16x-48

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2) 3x^3=3x^2\cdot x, and 3x^2(x+2)=3x^3+6x^2. Subtracting this from the numerator gives a remainder of

(3x^3-x^2-7x+6)-(3x^3+6x^2)=-7x^2-7x+6

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(-12x-24)-(-12x-24)=0

and since the remainder is 0, x+2 is indeed a factor of x^3+3x^2-10x-24.

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