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miskamm [114]
3 years ago
14

What is the range of the function on the graph?

Mathematics
2 answers:
muminat3 years ago
7 0
The range of a function is the set of y-coordinates of all the points int he graph of the function.
Look at the graph. The vertex is point (2, -3).
The graph does not go lower than that point.
The lowest y-coordinate is -3.
The graph goes up forever on both sides until infinity.
The range is all numbers greater than or equal to -3.
Gekata [30.6K]3 years ago
7 0
All real number greater than or equal to -3.
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How do you determine if two numbers or expressions are equal
Alja [10]
You can determine if two numbers are equal if they have the same value. (4 are 4 are equal) (4 and 5 are not equal). You can determine if two expressions are equal by solving them. If the answers are of an equal value, they are equal. (4+5 and 6+3 are equal because they both work out to be 9) (4+5 and 5+5 are not equal because they work out to be 9 and 10.)
                                              ~Crutchie
p.s. The mathmatical term for "equal" is <em>equivilent. </em>As in <em>equivilent expressions</em> or <em>equivilent numbers</em>.


p.p.s. The mathmatical term for "numbers" are <em>integers</em>. As in <em>the diffrence between the integers </em>or <em>equivilent integers.</em>
7 0
3 years ago
PLLLLSSS HELP ME ASAP!
erastovalidia [21]
The answer to the first one is ' D '.
(All the angles inside a triangle have to add up to exactly 180 degrees.)

The answer to the second one is  ' C ' .
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3 0
3 years ago
A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height
Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

y(t)=43t-23t^{2}

B) Instantaneous Velocity at t = 1

y(1) = 43(1)-23(1)^2 = 20

A) Formula:

Average velocity =

\displaystyle\frac{\text{Displacement}}{\text{Time}}

1) 0.01

y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}

2) 0.005 s

y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}

3) 0.002 s

y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}

4) 0.001 s

y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}

3 0
3 years ago
Please solve for 25 points...
xeze [42]

Answer:

if y intercepts than it should be b

Step-by-step explanation:

5 0
3 years ago
To order a class ring, students must decide on a gold, silver, or white gold band and one of 18 stones. They must also choose fr
Alex787 [66]

multiply the 3 choices together


3*18*20 = 1080

5 0
3 years ago
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