Given:
Capacity of jet plane = 200,000 liters of fuel
Fuel used during flight = 130,000 liters
To find:
The percentage of the fuel capacity it uses on this flight.
Solution:
According to the question, we need to find 130,000 is what percent of 200,000.
Therefore, the jet plane uses 65 percent of fuel capacity during flight.
Answer:
To make a table u need to have coordinates, (x, y).
Solve for them using substitution:
y = x - 4 ↔ x = y + 4
y = (2x - 17)
PLUG IN TO y = (2x - 17).
y = (2(y+4) - 17)
Solve for y:
y = 2y + 8 - 17
y = 2y - 9
-1y = -9
y = 9
Solve for x:
x = (9) + 4
x = 13
Keep solving for x and y to have your coordinates for your table.
Answer:
-18
Step-by-step explanation:
3 to the power of 9 over 10
Factor out sin x
Sin x (sinx +1) = 0
Use the zero product property
Sin x=0
Sin x+1 = 0
Solutions
x= 0 degrees
x= 270 or -90 degrees
