Question

A surveyor needs to determine the distance across the pond as shown in the diagram. He determines that the distance from his position to point y on the south shore of the pond is 200 meters and the angle from his position to point x on the north shore is 32°. What is the distance, to the nearest meter, across the pond?

Answer 1

Answer:

125 meter.

Step-by-step explanation:

After Reading the question we can draw the figure which is triangle XPS

given below.

The point S denotes the Surveyor who is at distance 200 from the south shore(P) and this point P is at y distance from North shore (X) and also the angle given is 32 degree.

So in triangle XPS right angled at P

$tan 32=\frac{XP}{PS}\\ tan 32=\frac{y}{200}\\ y=200*tan32\\y=124.97\\y=125(nearest meter).$