All categories

3 years ago

Please if anyone knows the answer to number 6

Mathematics

1 answer:

Inessa [10]3 years ago

4 0

N = (____)*h + (_____)

n = (_m__)*h + (___b__)

b is y-intercept, the number of radios when times = 0h
b=24

Slope is change in number of radios in 1 hour. Decreases by 2 means (-2).
m= - 2

So,
n= - 2h + 24

You might be interested in

3 times the amount of x+2? it is worth 10 points and

FinnZ [79.3K]

Not too sure what you're asking, but...

3(x+2) is the expression

8 0

3 years ago

Read 2 more answers

Reduce 8/4 what is the lowest number

nika2105 [10]

The lowest number is 2/1 or 2.

reduce 8/4 to 4/2 which can be reduced to 2/1

4 0

2 years ago

Read 2 more answers

PLZ do my techer assighned lession plzzz il give you anything and school is almost over plzzzz help me :(

Mekhanik [1.2K]

Answer: what is it?

Step-by-step explanation:

6 0

2 years ago

Find the volume of this rectangular pyramid,

Karo-lina-s [1.5K]

Answer:

56 cubic meter

Step-by-step explanation:

Volume of a pyramid: V=(lwh)/3

So then 7*3*8/3= 7*8 =

56 cubic meter

7 0

2 years ago

Solve the equation <img src="https://tex.z-dn.net/?f=%2835%20x%5E%7B4%7D%20y%2B14%20x%5E%7B5%7D%20y-2%20y%5E%7B3%7D-4x%20y%5E%7B

jeka94

$\underbrace{35x^4y+14x^5y-2y^3-4xy^3}_M\,\mathrm dx+\underbrace{7x^5-6xy^2}_N\,\mathrm dy=0$

$M_y=35x^4+14x^5-6y^2-12xy^2$
$N_x=35x^4-6y^2$

$\dfrac{N_x-M_y}N=\dfrac{-14x^5+12xy^2}{7x^5-6xy^2}=-2$

This suggests an integrating factor depending on $x$ only is possible, and given by

$\mu(x)=\exp\left(-\displaystyle\int\frac{N_x-M_y}N\,\mathrm dx\right)=e^{2x}$

Distributing across the ODE, we end up with

$\underbrace{(35x^4y+14x^5y-2y^3-4xy^3)e^{2x}}_{M^*}\,\mathrm dx+\underbrace{(7x^5-6xy^2)e^{2x}}_{N^*}\,\mathrm dy=0$

The equation is now exact, with

${M^*}_y={N^*}_x=(35x^4+14x^5-6y^2-12xy^2)e^{2x}$

Now we find the solution:

$F_x=M^*$
$F=\displaystyle\int(35x^4+14x^5-2y^3-4xy^3)e^{2x}\,\mathrm dx$
$F=(7x^5y-2xy^3)e^{2x}+f(y)$

$F_y=N^*$
$(7x^5-6xy^2)e^{2x}+f'(y)=(7x^5-6xy^2)e^{2x}$
$f'(y)=0$
$\implies f(y)=C$

The general solution is then

$F(x,y)=(7x^5y-2xy^3)e^{2x}=C$

7 0

3 years ago