All categories

3 years ago

Twelve more than seven times a number equals the number less six. what is the solution?

Mathematics

1 answer:

xenn [34]3 years ago

7 0

Answer:12+17(x)<6

Step-by-step explanation:

You might be interested in

A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6

ddd [48]

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

Now, According to question

The population of bacteria after 6 days = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, f = i × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, f = 1000 × $(1+\dfrac{\textrm 15}{100})^{\textrm 6}$

Or, f = 1000 × $(1.15)^{6}$

Or, f = 1000 × 2.31306

∴ f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06 Answer

3 0

3 years ago

With instructions too please

irga5000 [103]

Answer on pic above

Hope this helps

7 0

3 years ago

Find the slope of the line passing through the points -4,-3 and 8,-9

Dafna11 [192]

Answer:

-3/4

Step-by-step explanation:

Slope = Rise/Run

Between -4 and 8, the line runs 12 units. Between -3 and -9, the line rises -9 units.

-9/12 = -3/4

8 0

3 years ago

Read 2 more answers

What is the solution for 5x + 2/5 using a replacement set of {1/5, 2/5 7/10}?

-Dominant- [34]

Oh man I think its 2/5

3 0

3 years ago

Simplify by factoring. Assume that all expressions under radicals represent nonnegative numbers.

Nimfa-mama [501]

<h2>Answer:</h2>

x>0 and working with real numbers

$10x^2\sqrt{2}$

x<0 and working with imaginary/complex numbers

$10\sqrt{2}\sqrt{x^4}$

Leave it like the following for both systems(Real/Complex) numbers

$10\sqrt{2}\sqrt{x^4}$

<h2>Step-by-step explanation:</h2>

$\sqrt{200x^4}$

First simplify $\sqrt{200}$

$\sqrt{200}$

Find a perfect square and a non perfect square, which when you multiply the two squares it gives you $\sqrt{200}$

$\sqrt{100} * \sqrt{2} = \sqrt{200}$

$\sqrt{100} \ \sqrt{2}}$

$10 \sqrt{2}$

Now get the square root of $\sqrt{x^4}$ if we are working with real numbers and x > 0

$\sqrt{x^4} = x^2$

If x not > 0 then just leave as $\sqrt{x^4}$

Now combine it all

$10x^2\sqrt{2}$

$10\sqrt{2}\sqrt{x^4}$

5 0

3 years ago