That would be
![x = + \frac{ \sqrt[]{3} }{ \sqrt[]{2} }](https://tex.z-dn.net/?f=x%20%3D%20%20%2B%20%5Cfrac%7B%20%5Csqrt%5B%5D%7B3%7D%20%7D%7B%20%5Csqrt%5B%5D%7B2%7D%20%7D%20)
BTW the plus sign is supposed to have this sign underneath it _
Good luck.
Answer:
-35/4
Step-by-step explanation:
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4
Answer:
40 Tickets
80 Tickets
Step-by-step explanation:
To find how many tickets it will take to break even, we use the formula:

Our variables are:
Fixed Cost = $200
Sales Price = $10
Variable Cost = $5
Let's plug in our values into the formula.



So the class needs to sell a total of 40 Tickets to break even.
Since we know that it takes 40 tickets to break even a $200 Fixed cost. To make a profit of $200, we simply multiply the number of tickets sold by 2.
Number of tickets for $200 profit = 40 x 2
Number of tickets for $200 profit = 80 Tickets.
So the class needs to sell 80 Tickets to make a $200 Profit.
Answer:
The number of horses that can eat 4 stacks of hay in 8 days = 56 horses
Step-by-step explanation:
The given parameters are;
The time it takes 16 horses to eat 5 stacks = 35 days
Therefore;
The time it takes 16 horses to eat 5/5 stacks (1 stack) = 35 days/5 = 7 days
The time it takes 16 horses to eat 1 stack of hay = 7 days
The time it takes 16 horses/16 to eat 1 stack of hay = 7 days × 16 = 112 days
Therefore;
The time it takes 1 horse to eat 1 stack of hay = 112 days
The time it takes 1 horse to eat 4 × 1 stack of hay = 112 days × 4 = 448 days
The time it takes 1 horse to eat 4 stacks of hay = 448 days
Therefore, given that (448 days)/(8 days/horse) = 56 horse, we have;
The number of horses that will eat 4 stacks of hay in 8 days = 56 horses.