Question

5. The table shows the total vertical distance a free-falling body travels for each second it falls. About how far does the free-falling body travel between 4 and 5 seconds? a. 44 m b. 54 m c. 144 m d. 154 m

Answer 1

Answer:

a. 44 m

Explanation:

We don't have the table but we can still answer since the motion is a free-fall motion.

First of all, we calculate the velocity of the body at time t = 4 s, with the equation

$u'=u+gt$

where

u = 0 is the initial velocity

g = 9.8 m/s^2 is the acceleration of gravity (we take downward as positive direction)

t is the time

Using t = 4 s,

$u'=0+(9.8)(4)=39.2 m/s$

Now we can calculate the distance covered during the time t = 4 s and t = 5 s using the other suvat equation

$s=u'\Delta t+\frac{1}{2}g\Delta t^2$

where

$\Delta t = 5-4=1s$ is the time interval we are considering. Substituting values,

$s=(39.2)(1)+\frac{1}{2}(9.8)(1)^2=44 m$