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3 years ago

15

Fill in the missing words thats all but I don't know so yeah

1 answer:

lesya692 [45]3 years ago

5 0

Copy and paste the definitions

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An engine is designed to obtain energy from the temperature gradient of the ocean. What is the thermodynamic efficiency of such

rewona [7]

Answer:

0.035 (3.5 %)

Explanation:

The thermodynamic efficiency is given by:

$\eta = 1 - \frac{T_C}{T_H}$

where

$T_C$ is the cold temperature

$T_H$ is the hot temperature

In this problem we have

$T_C = 5 ^{\circ}C+ 273 = 278 KT_H = 15^{\circ}C+273 = 288 K$

So the efficiency is

$\eta = 1 - \frac{278 K}{288 K}=0.035$

6 0

3 years ago

A tree is blank relative to earth a tree is blank relative to the sun

Ray Of Light [21]

hmmmmmmmmmmmmmmmmm ask someone else sorry if im not helping

7 0

3 years ago

Your go-cart breaks down right before the end of a race, so you have to push it over the finish line. The go-cart has a mass of

Flura [38]

a) W=mg=833 N by definition

b) F=ma=76.5 N according to Newton's second law

c) a=F/m=4.12 m/s^2

d) m=F/a=720/5.5=130.91 kg

6 0

3 years ago

Solve for angles A-D

patriot [66]

B = 53°

Reason: Opposite angles

A = 37°

Reason: Sum of angels on a straight line = 180 so 180-90-53 = 37°
C = 90°

Reason: Right angles = 90°

D = 37°

Reason: Sum of angels on a straight line = 180 so 180-90-53 = 37°

7 0

4 years ago

A baseball pitcher throws a baseball horizontally at a linear speed of 42.5 m/s (about 95 mi/h). Before being caught, the baseba

Xelga [282]

Answer:

$v_t=46.4532\ m.s^{-1}$

Explanation:

Given:

Linear horizontal speed of the ball, $v_x=42.5\ m.s^{-1}$

distance travelled by the ball, $x=17.4\ m$

angle rotated by the ball, $\theta=44.1\ rad$

radius of the ball, $r=3.67\ cm=0.0367\ m$

<u>the time for which the ball travels:</u>

$t=\frac{x}{v_x}$

$t=\frac{17.4}{42.5}$

$t=0.4094\ s$

<u>Angular speed of the ball:</u>

$\omega=\frac{\theta}{t}$

$\omega=\frac{44.1}{0.4094}$

$\omega=107.7155\ rad.s^{-1}$

<u>Now the tangential speed at the equator of the ball:</u>

$v_t=r.\omega+v_x$ (the tangential speed due to rotation and the linear speed are having the same direction)

$v_t=0.0367\times 107.7155+42.5$

$v_t=46.4532\ m.s^{-1}$

4 0

4 years ago