Using the law of conservation of angular momentum, we have
<span>I1 w1 = I2 w2 </span>
<span>ie., m1r^2/2 x w1 = ( m1r^2/2 + m2r^2 ) w2 </span>
<span>ie., new angular velocity w2 = m1 w1 / ( m1+ 2m2) = 125 x 3.1 / ( 125 + 2 x39.5 ) </span>
<span>= 1.8995 = 1.9 rad /sec ( nearly )</span>
Answer:
B. 1.55 × 10³ m/s
Explanation:
f = 3.02 x 10^6 Hz
wavelength = 5.13 x 10^-4 m
v = ?
v = f*lamda
v = 3.02 x 10^6 × 5.13 x 10^-4
v = 1.55 × 10³ m/s
The minimum frequency is

while the maximum frequency is

Using the relationship between frequency f of a wave, wavelength

and the speed of the wave v, we can find what wavelength these frequencies correspond to:


So, the wavelengths of the radio waves of the problem are within the range 188-545 m.