To be able to determine the graph of this inequality, we'll start rearranging the inequality putting the "y" variable at the left side of the equation.
Since the inequality here is greater than or equal to, this means that the shade is above the solid line.
This equation also has a slope of -5 and y-intercept of 0.
Therefore, the graph of this equation looks like this:
Complete part of Question:
Assume a factor of safety of 3.0
The Maximum stress versus logarithm of the number of cycles to fatigue failure curve for 2014-T6 Aluminium bar is attached to this solution
Answer:
The maximum allowable load amplitude is 6403.33 N
Step-by-step explanation:
diameter of the bar, d = 12 mm
d = 0.012 m
Cross sectional area of the bar, A = πd²/4
A = π*0.012²/4
A = 0.000113 m²
From the Maximum stress versus logarithm of the number of cycles to fatigue failure for 2014-T6 Aluminium bar attached to this solution;
At 10⁷ cycles, Maximum stress, S = 170 MPa
S = 170 * 10⁶ Pa
Factor of safety, N = 3.0
The tensile stress is given by the formula:
The tensile stress is also given by:
F/0.000113 = 56.67 * 10⁶
F = 56.67 * 10⁶ * 0.000113
F = 6403.33 N
The maximum allowable load amplitude is 6403.33 N
