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Serhud [2]
3 years ago
8

give an example if an equation where any value if X will make the equation true. Infinite number of solutions. PLS HELP

Mathematics
1 answer:
defon3 years ago
8 0

Answer:

x+3 = x+3

Step-by-step explanation:

No matter what you plug into x, both sides will be the same.

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Choose the equation below that represents the line that passes through the point (7, -2) and has a slope of -3
Norma-Jean [14]

Answer:

Option C

Step-by-step explanation:

All of these equation have a slope of x=-3, as this is the only number that will be acompanied by an x (the slope of a function is the number on the equation that has an X). To know which one of this equations passes through the points (7;-2) we can supplant these numbers on each equation until the result at both sides are equals.

The correct answer is the option c, because if we supplant these numbers (x=7 and y=-2) on the equation, we get an equality.

y + 2  = -3. (x - 7) // -2 + 2 = -3. (7 - 7) //0 = 0

7 0
4 years ago
What things do you need to remember to estimate large numbers
irga5000 [103]

Answer:

remember to round numbers to 1 significant figure

Step-by-step explanation:

usually in an exam when you're asked to estimate the answer to a calculation, usually you round each number to 1 sf and then work on from there.

3 0
3 years ago
Find sin R.<br> a. sin R= 29/21<br> b. sin R= 21/20<br> c. sin R= 20/29<br> d. sin R= 21/29
krok68 [10]

Answer:

sin R = 20 / 29

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin R = opp / hyp

sin R = 20 / 29

4 0
3 years ago
Select the correct answer from each drop-down menu. Shape I is similar to shape II. The sequence that maps shape I onto shape II
AURORKA [14]

Answer:

Scale factor 2.

Step-by-step explanation:

The vertices of shape I are (2,1), (3,1), (4,3), (3,3), (3,2), (2,2), (2,3), (1,3).

The vertices of shape II are (-4,-2), (-6,-2), (-8,-6), (-6,-6), (-6,-4), (-4,-4), (-4,-6), (-2,-6).

Consider shape I is similar to shape II. The sequence that maps shape I onto shape II is a 180 degree clockwise rotation about the origin, and then a dilation by a scale factor of k.

Rule of 180 degree clockwise rotation about the origin:

(x,y)\rightarrow (-x,-y)

The vertices of shape I after rotation are (-2,-1), (-3,-1), (-4,-3), (-3,-3), (-3,-2), (-2,-2), (-2,-3), (-1,-3).

Rule of dilation by a scale factor of k.

(x,y)\rightarrow (kx,ky)

So,

(-2,-1)\rightarrow (k(-2),k(-1))=(-2k,-k)

We know that, the image of (-2,-1) after dilation is (-4,-2). So,

(-2k,-k)=(-4,-2)

On comparing both sides, we get

-2k=-4

k=2

Therefore, the scale factor is 2.

4 0
4 years ago
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N^2 +3n+6 / n (as a fraction)
8 0
4 years ago
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