The formula for the radius r in terms of x . and for the maximum areas is x=2/
+4
Given that,
y forms a circle of radius r
y=2r
r=y/2
(2-y)- forms Square Side x
(2-y) = 4x
x=(2-y)/4
Now Sum of Area's=Area of Square +Area of Circle
Sum = r² + x²
Substitute the r and x values in above equation,
A(y)= y²/4+(y-2)²/ 16
To maximize Area A(y)
A'(y)= 0
2y/4 + 2(y-2)/16 =0
y/2 + (y-2)/8 =0
y = 2/+4
Y max will be max, x to be maximum.
for maximum sum of areas,
x=2/+4
Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/+4
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Answer: you got this
Step-by-step explanation:
Ok as sqrt(x^6 + 5) approaches infinity it goes to x^3
Same with the denominator because x^3 is the highest power
On the bottom, the factor on x^3 is 4 so on the top to make the limit evaluate to 1/3, a has to be 16/9 so then when you neglect all of the other powers besides the highest, it goes to 4/3 because you take the square root and then it simplifies to 1/3
Answer:
7
Step-by-step explanation:
difference between two number let say x&y is x-y
so, difference between their score is (-17)-(-24)
=(-17)+24 {minus of minus is plus}
=24-17
=7
