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PtichkaEL [24]
3 years ago
8

Find a general term an for the sequence whose first four terms are given. 2, 4, 8, 16, ...

Mathematics
1 answer:
lapo4ka [179]3 years ago
7 0

Answer:

  an = 2·2^(n-1)

Step-by-step explanation:

There are simple tests to determine whether a sequence is arithmetic or geometric. The test for an arithmetic sequence is to check to see if the differences between terms are the same. Here the differences are 2, 4, 8, so are not the same.

The test for a geometric sequence is to check to see if the ratios of terms are the same. Here, the ratios are ...

  4/2 = 2

  8/4 = 2

  16/8 = 2

These ratios are all the same (they are "common"), so the sequence is geometric.

The general term of a geometric sequence with first term a1 and common ratio r is ...

  an = a1·r^(n-1)

Filling in the values for this sequence, we find the general term to be ...

  an = 2·2^(n-1)

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Nutka1998 [239]
Set as a proportion
16 = 12
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5x+2 24

cross multiply
12(5x+2) = 16 * 24
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60x/60=360/60
x =6

To figure AB plug 6 into 5x+2
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5(6) + 2
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4 0
2 years ago
Which number is greatest? 2.89 times 10 Superscript negative 8 1.997 times 10 Superscript 2 8.9 times 10 Superscript negative 6
love history [14]
<h3> The greatest number is 1.997 \times 10^2</h3>

<em><u>Solution:</u></em>

<em><u>Given that the numbers are:</u></em>

2.89 \times 10^{-8}\\\\1.997 \times 10^2\\\\8.9 \times 10^{-6}\\\\5 \times 10^{-6}

We have to find the number that is greatest

Convert the numbers to decimal

2.89 \times 10^{-8} = 2.89 \times \frac{1}{10^8} =0.0000000289

1.997 \times 10^2 = 199.7

8.9\times 10^{-6}=8.9\times \frac{1}{10^6}=0.0000089

5\times 10^{-6}=5\times \frac{1}{10^6}=0.000005

We can clearly see that, 199.7 is greatest number

Thus the greatest number is 1.997 \times 10^2

3 0
3 years ago
Read 2 more answers
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Romashka [77]
Number one ☝️ right maybe
7 0
3 years ago
Please help it’s a practice test
zaharov [31]

slope intercept form is y = mx + b

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4 0
3 years ago
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Convert r=sec thaeta to rectangular form
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Multiply both sides by <span>cos</span><span>
</span><span>r<span>cos<span>(θ)</span></span>=<span>sec<span>(θ)</span></span><span>cos<span>(θ)</span></span>=1</span><span>
</span><span>x=r<span>cos<span>(θ)</span></span></span><span>
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3 0
3 years ago
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