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Debora [2.8K]
3 years ago
7

Thomas and Lilian are walking down the street to get to the corner store. They walk 5 blocks up the street and turn right by the

stop sign. Once they turn at the stop sign they continue walking for 8 more blocks. They make a left, walk 2 blocks and cross the street to arrive at the corner store. While there they purchase a few snacks, sit at the curb, and then walk back home where they originally started. Thomas and Lilian are discussing their walk in reference to their overall displacement and distance. They seem to be in disagreement about their journey. Thomas says their overall displacement and distance are both zero, because they are back where they started. Lilian thinks their total distance and displacement are greater than zero.
Which person do you most agree with?
You are not expected to actually calculate in order to solve this problem.
Physics
1 answer:
vfiekz [6]3 years ago
4 0

Answer:

Thomas is correct that the zero displacements

Lilian is right that the distance is greater than zero.

Explanation:

In this problem we have to be clear about the difference between displacement and distance.

The displacement is a vector, that is, it has a modulation and direction, in this case we can draw a vector for the outward trip and another vector for the return trip, both will have the same magnitude, but their directions are opposite, so the resulting vector is zero.

The distance is a scalar and its value coincides with the modulus of the distance vector, in our case the distance is d for the outward journey and d for the return journey, so the total distance is 2d, which is different from zero.

The two students have some reason, but neither complete,

The displacement is zero because it is a vector and

the distance is different from zero (2d) because it is a scalar

 

Thomas is correct that the zero displacements

Lilian is right that the distance is greater than zero.

Therefore I agree with both, because each one has a 50% of the reason

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a block of mass m slides along a frictionless track with speed vm. It collides with a stationary block of mass M. Find an expres
shusha [124]

Answer:

Part a) When collision is perfectly inelastic

v_m = \frac{m + M}{m} \sqrt{5Rg}

Part b) When collision is perfectly elastic

v_m = \frac{m + M}{2m}\sqrt{5Rg}

Explanation:

Part a)

As we know that collision is perfectly inelastic

so here we will have

mv_m = (m + M)v

so we have

v = \frac{mv_m}{m + M}

now we know that in order to complete the circle we will have

v = \sqrt{5Rg}

\frac{mv_m}{m + M} = \sqrt{5Rg}

now we have

v_m = \frac{m + M}{m} \sqrt{5Rg}

Part b)

Now we know that collision is perfectly elastic

so we will have

v = \frac{2mv_m}{m + M}

now we have

\sqrt{5Rg} = \frac{2mv_m}{m + M}

v_m = \frac{m + M}{2m}\sqrt{5Rg}

6 0
4 years ago
A typical human lens has an index of refraction of 1.430 . The lens has a double convex shape, but its curvature can be varied b
rjkz [21]

Answer:

Maximum Power = 144.3 D

The associated focal length of the lens = 6.92*10^{-3} m

Explanation:

According to the Lens maker's Formula:

\frac{1}{f} = (n-1) (\frac{1}{R_1}-\frac{1}{R_2}  )

where;

n_1 = the refractive index of the medium

R_1 and R_2 = radius of curvature on each surface

For a convex lens, The radius of curvature in the front surface will be positive and that of the second surface will be negative . Therefore;

\frac{1}{f} = (n-1) (\frac{1}{R_1}-\frac{1}{-R_2}  ) \\ \\ \frac{1}{f} = (n-1) (\frac{1}{R_1}+\frac{1}{R_2}  )

At maximum power

\frac{1}{f} = (1.430-1) (\frac{1}{6.50 \ mm}-\frac{1}{5.50 \ mm}  )

= 0.144 \ mm^{-1}

This Implies

f = 6.92 mm\\f = 6.92*10^{-3} \ m

Therefore; the power is given by the formula:

P_{max} = \frac{1}{f}

P_{max}= \frac{1}{6.92*10^{-3}}

= 144.3 D

3 0
4 years ago
A truck with a mass of 1330 kg and moving with a speed of 15.0 m/s rear-ends a 805 kg car stopped at an intersection. The collis
Dovator [93]

Answer:

The Speed of the vehicles is 9.34m/s

Explanation:

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M1V1+M2V2=(M1+M2)V

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8 0
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Hence the best statements about X- ray will be-

1- X -rays are electromagnetic waves

2-X-rays are transverse transverse waves

3- X- rays travel at the speed of light.


5 0
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Answer:

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Explanation:

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