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Elena L [17]
4 years ago
12

Find the distance between two slits that produces the first minimum for 410-nm violet light at an angle of 45.0°

Physics
1 answer:
Tpy6a [65]4 years ago
6 0

Answer:

Distance between slits, d=2.89\times 10^{-7}\ m  

Explanation:

It is given that,

Wavelength, \lambda=410\ nm=410\times 10^{-9}\ m

Angle, \theta=45

We need to find the distance between two slits that produces first minimum. The equation for the destructive interference is given by :

d\ sin\theta=(n+\dfrac{1}{2})\lambda

For first minimum, n = 0

So, d\ sin\theta=(\dfrac{1}{2})\lambda

d is the distance between slits

So, d=\dfrac{1/2\lambda}{sin\theta}

d=\dfrac{1/2\times 410\times 10^{-9}}{sin(45)}

d=2.89\times 10^{-7}\ m

So, the distance between two slits is 2.89\times 10^{-7}\ m. Hence, this is the required solution.

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