The net current in the conductors and the value of the line integral

- The resultant remains same 3.2 *10^4 Tm
This is further explained below.
<h3>What is the net current in the conductors?</h3>
Generally,
To put it another way, the total current In flowing across a surface S (contained by C) is proportional to the line integral of the magnetic B-field (in tesla, T).


B)
In conclusion, It is possible for the line integral to go around the loop in either direction (clockwise or counterclockwise), the vector area dS to point in either of the two normal directions and Ienc, which is the net current passing through the surface S, to be positive in either direction—but both directions can be chosen as positive in this example. The right-hand rule solves these ambiguities.
The resultant remains the same at 3.2 *10^4 Tm
Read more about conductors
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23) 560 cm
25) 3100 mg
27) 8.89 cm
29) 525 g
31) I can't see the measurement it needs to be converted to
Answer:
1.9 s
Explanation:
We are given that
Length of cable=l=15 m
We have to find the time you have to move out of the way.
We know that
Time period,T=
Where g=
By using the formula


Time you have to move out

Hence,time you have to move out of the way=7.77 s
<h2>
Answer: a definition of the term black hole</h2>
This text is clearly a definition of the term black hole, made by the American astrophysicist Neil deGrasse Tyson.
However, the discussions about this subject are not new, since Einstein's theory of relativity already defined what a black hole is.
In this sense, a black hole is described as a "singularity" that consists of <u>a region of the space in which the density of matter tends to infinity.</u>
Although this is hard to find possible for classical physics; following what relativity establishes:<em> bodies within a gravitational field follow a curved space path. Then the more a body enters the black hole, the more curved the space will become, until, in the center, it will become infinitely curved. </em>
Answer:
gs = 0.6 m/s^2
Explanation:
Given data:
velocity = 12 m/s
height s = 12t -(1/2) g_s t^2
Given velocity is the derivatives of height



when velocity tend to 0 , maximum height is reached



at t = 20 sec ball reached the max height, so
