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Aleks [24]
3 years ago
15

Choose all the answers that apply.

Physics
2 answers:
NARA [144]3 years ago
6 0
Moves in waves, cannot be created, the ability to do work, and can change form (potential to kinetic and vice versa).



stiv31 [10]3 years ago
4 0

Answer:

*Moves in waves

*Cannot be created

*Is the ability to do work

*Can change form

Explanation:

You might be interested in
A closed curve encircles several conductors. The line integral around this curve is (image attached below)
Masteriza [31]

The net current in the conductors and the value of the line integral

  • I=\frac{3.2\cdot 10^{-4}}{4\pi \cdot 10^{-7}}=254.77\, A
  • The resultant remains same 3.2 *10^4 Tm

This is further explained below.

<h3>What is the net current in the conductors?</h3>

Generally,

To put it another way, the total current In flowing across a surface S (contained by C) is proportional to the line integral of the magnetic B-field (in tesla, T).

\oint_C \mathbf{B} \cdot \mathrm{d}\boldsymbol{\ell} = \mu_0 \iint_S \mathbf{J} \cdot \mathrm{d}\mathbf{S} = \mu_0I_\mathrm{enc}

I=\frac{3.2\cdot 10^{-4}}{4\pi \cdot 10^{-7}}=254.77\, A

B)

In conclusion, It is possible for the line integral to go around the loop in either direction (clockwise or counterclockwise), the vector area dS to point in either of the two normal directions and Ienc, which is the net current passing through the surface S, to be positive in either direction—but both directions can be chosen as positive in this example. The right-hand rule solves these ambiguities.

The resultant remains the same at 3.2 *10^4 Tm

Read more about conductors

brainly.com/question/8426444

#SPJ1

5 0
2 years ago
I need help on the question that are blank
cluponka [151]
23) 560 cm
25) 3100 mg
27) 8.89 cm
29) 525 g
31) I can't see the measurement it needs to be converted to
6 0
3 years ago
A building is being knocked down with a wrecking ball, which is a big metal sphere that swings on a 15-m-long cable. You are (un
Charra [1.4K]

Answer:

1.9 s

Explanation:

We are given that

Length of cable=l=15 m

We have to find the time you have to move out of the way.

We know that

Time period,T=2\pi\sqrt{\frac{l}{g}}

Where g=9.8m/s^2

By using the formula

T=2\pi\sqrt{\frac{15}{9.8}}

T=2\times 3.14\times \sqrt{\frac{15}{9.8}}=7.77 s

Time you have to move out

t=\frac{T}{4}=\frac{7.77}{4}=1.9 s

Hence,time you have to move out of the way=7.77 s

6 0
4 years ago
Read the excerpt from Neil deGrasse Tyson’s “Death by Black Hole.” Black holes are regions of space where the gravity is so high
kramer
<h2>Answer: a definition of the term black hole</h2>

This text is clearly a definition of the term black hole, made by the American astrophysicist Neil deGrasse Tyson.

However, the discussions about this subject are not new, since Einstein's theory of relativity already defined what a black hole is.

In this sense, a black hole is described as a "singularity" that consists of <u>a region of the space in which the density of matter tends to infinity.</u>

Although this is hard to find possible for classical physics; following what relativity establishes:<em> bodies within a gravitational field follow a curved space path. Then the more a body enters the black hole, the more curved the space will become, until, in the center, it will become infinitely curved. </em>

4 0
3 years ago
Read 2 more answers
Explorers on a small airless planet used a spring gun to launch a ball bearing vertically upward from the surface at a launch ve
Oksana_A [137]

Answer:

gs = 0.6 m/s^2

Explanation:

Given data:

velocity = 12 m/s

height s = 12t -(1/2) g_s t^2

Given velocity is the derivatives of  height

v(t) = \frac{d}{dt} s(t)

      = \frac{d}{dt}(12t -\frac{1}{2} g_s t^2)

      = 12 - g_s t

when velocity tend to 0 , maximum height is reached

v(t) = 12 - g_s t

0 = 12 - g_s t

g_s = \frac{12}{t}

at t = 20 sec ball reached the max height, so

g_s = \frac{12}{20} = 0.6 m/s^2

5 0
3 years ago
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