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Natali [406]
3 years ago
13

Similarities and differences between distance Time graph and velocity time graph?

Physics
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

Similarity: >>Time is independent variable and such is on the x-axis. ... >>Distance time graph tells you how much distance you have travelled, while velocity time graph tells you your acceleration.  The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.

Explanation:

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A wave has an amplitude of 0.2 cm.
Anettt [7]
The distance between the resting point and maximum height of the wave is 0.2 cm.

The amplitude is measured from the resting point up to the highest point of the wave.
3 0
2 years ago
Calculate the translational speed of a cylinder when it reaches the foot of an incline 7.05 mm high. Assume it starts from rest
mestny [16]

Height is 7.05 m and not 7.05 mm

Answer:

9.603 m/s

Explanation:

We are dealing with rotation, so velocity of centre of mass is given by;

v_cm = Rω

Since we are working with a solid cylinder, moment of inertia of the cylinder is; I = ½mR²

Since it is rolled from the top to the bottom, at the top it will have potential energy(mgh) while at the bottom it will have kinetic energy (rotational plus translational kinetic energy).

Using conservation of energy, we have:

P.E = K.E_t + K.E_r

Formula for rotational and kinetic energy here are;

K.E_t = ½mv²

K.E_r = ½Iω²

mgh = ½mv² + ½Iω²

Since we want to find translational speed(v), let's get rid of ω.

Earlier, we saw that v_cm = Rω

Thus; ω = v/R

Also, we know that I = ½mR².

Thus;

mgh = ½mv² + ½(½mR²)(v/R)²

This gives;

mgh = ½mv² + ¼mv²

Divide through by m to get;

gh = v²(½ + ¼)

gh = ¾v²

Making v the subject gives;

v = √(4gh/3)

v = √((4 × 9.81 × 7.05)/3)

v = 9.603 m/s

6 0
2 years ago
A ball is thrown with a velocity of 10 m/s at a 25º from the horizontal. How far does the ball travel?
Stels [109]

Answer:

use a=v-u/t formula it will be correct

5 0
3 years ago
What are (a) the x component and (b) the y component of a vector in the xy plane if its direction is 259° counterclockwise from
garik1379 [7]

Answer:

|Ax| =1.03 m  (directed towards negative x-axis)

|Ay|= 5.30 (directed towards negative y-axis)

Explanation:

Let A is a vector = 5.4 m

θ = 259°

to Find Ax, Ay

Sol:

according the condition it lies in 3rd quadrant

we know that Horizontal Component Ax = A cos θ

Ax = 5.4 Cos 259°

Ax = - 1.03 m

|Ax| =1.03 m  (directed towards negative x-axis)

Now Ay = A sin θ

Ay = 5.4 Sin 259°

Ay = -5.30

|Ay|= 5.30 (directed towards negative y-axis)

3 0
3 years ago
Read 2 more answers
One end of a copper rod is in thermal contact with a
Gwar [14]

Answer:

\Delta S_1=-16\ J/K

\Delta S_2=26.66\ J/K

ΔS= 10.66 J/K

Explanation:

Given that

For hot reservoir :

T₁= 500 K

For cold reservoir :

T₂= 300 K

Energy transfer ,Q= 8000 J

The entropy change for the Hot reservoir :

\Delta S_1=-\dfrac{Q}{T_1}

\Delta S_1=-\dfrac{8000}{500}

\Delta S_1=-16\ J/K

The entropy change for the cold  reservoir :

\Delta S_2=\dfrac{Q}{T_2}

\Delta S_2=\dfrac{8000}{300}

\Delta S_2=26.66\ J/K

The entropy for universe

ΔS=ΔS₁+ΔS₂

ΔS= - 16 + 26.66 J/K

ΔS= 10.66 J/K

5 0
3 years ago
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