X = tuna, y = BLT
x + y = 30
6x + 9y = 240
3y = 60
y = 20
x = 10
20 BLTs for $2.50, 10 tuna for $1.50
Answer:
y=3/4x-2.5
Step-by-step explanation:
This is a straight line, so it would follow the equation y=mx+b. You can find the b value by looking at the y-intercept of the equation (where x=0), which in this case would be -2.5. Then, you can find the m value by comparing the two given points' locations. Slope is rise over run, so first you can find the rise. The y value moves from y=-4 to y=2, which is a value of 6 units upward. The points move from x=-2 to x=6, which is a distance of 8 units. Finally, put it into the rise over run pattern, giving you 6/8, which simplified is 3/4. This is your m value. Finally, plug in your two variable values into y=mx+b and you'll get y=3/4x-2.5.
0.25 = 25/100
to simplify 25/100, divide 25 from both the numerator and denominator.
25/25 = 1
100/25 = 4
1/4 is the simplest form
C. 1/4 is your answer
hope this helps
The number of microorganisms that I will have after 10 days would be: 245.41 microoganisms.
<h3>How to calculate the number of microorganisms that I will have after 10 days?</h3>
To calculate the number of microorganisms that I will have after 10 days, I must perform the following operations:
We need to find 37% of 55 as shown below:
- 55 ÷ 100 = 0.55
- 0.55 x 37% = 20.35
- 55 + 20.35 = 75.35
So after 2 days I will have 75.35 microorganisms.
- 75.35 ÷ 100 = 0.75
- 0.7535 x 37% = 27.87
- 75.35 + 27.87 = 103.22
On the fourth day I will have: 103.22 microorganisms.
- 103.22 ÷ 100 = 1.0322
- 1.0322 x 37% = 38.19
- 103.22 + 38.19 = 141.41
On the sixth day I will have 141.41 microorganisms.
- 141.41 ÷ 100 = 1.4141
- 1.4141 x 37% = 52.32
- 141.41 + 52.32 = 193,73
On the eighth day I will have 193.73 microorganisms.
- 193.73 ÷ 100 = 1.9373
- 1.9373 x 37% = 71.68
- 193.73 + 71.68 = 265.41
On the tenth day I will have 245.41 microoganisms.
Learn more about percentages in: brainly.com/question/13450942
#SPJ1
Answer:
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
sin(D) = 20/29
D = arcsin(20/29)
D=43.60281897 °
cos( 43.60281897 °)= DF / 29
DF = 29*cos( 43.60281897 °)
DF = 21
sin(D) = 20/29
cos(D) = 21/29
tan(D) = 20 / 21
sin(E) = 21/29
cos(E) = 20/29
tan(E) = 21 / 20
