The product of the lengths of the parts of the chord is equal to the product of the lengths of the parts of the chord that divides it.
(7 cm)*(8 cm) = n*(4 cm)
(7*8 cm²)/(4 cm) = n
14 cm = n
Let's work out the process to find the numerator:
(x+2)/2 - (x+1)/3x Factor using the LCD, 6x
3x(x+2)/6x - 2(x+1)/6x
(3x² + 6x - 2x - 2)/6x
= (3x² + 4x - 2)/6x
Answer is 3x² + 4x - 2
Hopefully I did this correct, Not to good with math c':
Options C and D as there is already a relationship between the numbers 1 and 2.
The 1st, 4th, and 7th terms make an arithmetic sequence of their own. The 4th term is the average of the 1st and 7th, so ...
(1st +7th)/2 = 4th
1st + 7th = 2×4th
1st = 2×4th - 7th
The first term is ...
2*141 - 132 = 150
