Answer: Yes they do.
Step-by-step explanation:
This because the ratio 10:1 means that for every 10 students that ride the bus only one walks. So if you had 30 students riding he bus you would only have 3 students that walked. So no matter what you will have more kids riding the bus.
Let V = the launch velocity
Let θ = the launch angle
Let d = the horizontal distance traveled
Ignore air resistance.
The horizontal component of velocity is
u = V cos θ
The time of flight is
t = d/(V cosθ) = (d/V) secθ
Create a table of θ versus t as shown below.
θ t/(d/V)
---- ----------
45 1.4142
40 1.3054
35 1.2208
30 1.1547
The graph shows that as the launch angle decreases below 45°, the time of flight decreases.
Therefore arrow b (θ < 45°) arrives first.
Answer: Arrow b arrives first.
You can identify similar polygon by comparing their corresponding angles and sides. ( if they are the same the ratio of the lengths is the scale factor. Also check if their sides are proportional.)
Answer:
Kwame's team will save = 7.8
$0.24 = $1.87
Step-by-step explanation:
i.) Let the side of the equilateral triangle base be a
ii.) the area of the base = 3.9 square feet
iii.) the area of equilateral triangle is =
= 3.9
iv.) Base area = 3.9 square feet
v.) The area that is not covered is the base.
vi.) The total area that is not covered = 3.9
2 since there are two pyramids
therefore the total area not covered = 7.8 square feet
vii.) therefore Kwame's team will save = 7.8
$0.24 = $1.87
Answer:

Step-by-step explanation:
The function <em>F(x)</em> is an antiderivative of the function <em>f(x)</em> on an interval <em>I</em> if
<em>F′(x)</em> = <em>f(x)</em> for all <em>x </em>in <em>I</em>.
The function <em>F(x) + C</em> is the General Antiderivative of the function <em>f(x)</em> on an interval <em>I</em> if <em>F′(x) = f(x)</em> for all <em>x</em> in <em>I </em>and <em>C</em> is an arbitrary constant.
The Indefinite Integral of <em>f(x)</em> is the General Antiderivative of <em>f(x)</em>.

To find the first antiderivative you must integrate the function 

To find the second antiderivative you must integrate the function 

Therefore,
