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3 years ago

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Kayli’s dad is 4 years less than 6 times Kayli’s age. Write a variable expression for the age of Kayli’s dad. Use x to represent

Kayli’s age.
REALLY NEED HELP!

1 answer:

quester [9]3 years ago

6 0

6x-4

hope this answers your question.

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Pls help me with my homework I need help

Mandarinka [93]

Answer:

need points luvk

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

<u>Answer-</u>

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

<u>Solution-</u>

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$

Now, equating this to 0

$(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}$

$\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}$

$\Rightarrow 2304e^{2x}-16e^{2x}-1=0$

Solving this eq,

we get $x= \frac{1}{2304e^4-16e^2}$

∴ At $x= \frac{1}{2304e^4-16e^2}$ the curvature is maximum.

6 0

3 years ago

A car traveling 65 mph leaves 25 ft skid mark. What is the ratio of the speed (mph) to the lenght of skid marks (ft) give you an

Pie

The answer is 13:5 I did this by dividing the numbers by a common factor

5 0

3 years ago

Simplify the expression <br><br> 12x^-6y^10X3x^7y

harkovskaia [24]

Answer:

12xy₁₁x₃

Step-by-step explanation:

4 0

3 years ago

Without using your calculator, decide which of these is larger: log8 62 or log7 50. How confident are you of your answer? Explai

nataly862011 [7]

Answer:

Step-by-step explanation:

log8 62 = x1

8^x1= 62

8^2 =64 >62 so <u>x1<2</u>

log7 50=x2

7^x2=50

7^2=49<50 so <u>x2>2</u>

we have, x1<2 and 2<x2

x1<2<x2

x1<x2

log8 62<log7 50

6 0

3 years ago