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german
3 years ago
15

Which of the following particles are free to drift in metals?

Chemistry
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

Electrons

Explanation:

"This free-floating collection of electrons gives metals many of their unique properties, and is sometimes called a “sea of electrons,”

Learn more about it at this website:

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=3&cad=rja&uact=8&ved=2ahUKEwjUw9Sbl7nmAhWQKs0KHXFGCakQFjACegQICxAK&url=https%3A%2F%2Futexaslearn.instructure.com%2Fcourses%2F2010099%2Fpages%2Fexplain-i-metallic-bonding-and-properties-2&usg=AOvVaw3B0fp0MY7ut9ssl_ebAgP7

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When an acid reacts with a base what compounds are formed?
vazorg [7]
It's usually water and a type of salt take the reaction between hydrochloric acid and sodium hydroxide HCl(aq)+NaOH(aq) yeilds NaCl(aq) and H2O(l) 
4 0
3 years ago
Read 2 more answers
Calculate the molarity of 13.1 g of NaCl in 727 mL of solution
valentina_108 [34]

Answer:

The molarity of the solution is 0,31 M

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g-----1 mol NaCl

13,1 g ---------x= (13,1 g x 1 mol NaCl)/58, 5 g= 0, 224 mol NaCl

727 ml solution------ 0, 224 mol NaCl

1000ml solution------x= (1000ml solutionx0, 224 mol NaCl)/727 ml solution

x=0,308 mol NaCl---> <em>The solution is 0,31 molar (0,31 M)</em>

5 0
3 years ago
How bad of alcoholic do you have to be to have your brain affected​
VLD [36.1K]

Answer:

Alcohol in Your Body

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Explanation:

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3 0
2 years ago
A sample of nitrogen gas has the temperature drop from 250.°c to 150.°c at constant pressure. what is the final volume if the in
Leviafan [203]
Charles law gives the relationship between temperature of gas and volume of gas.
It states that for a fixed amount of gas, temperature is directly proportional to volume of gas.
V / T = k
where   V- volume , T - temperature and k - constant 
\frac{V1}{T1} =  \frac{V2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
T1 = 250 °C + 273 = 523 K
T2 = 150 °C + 273 = 423 K
Substituting the values in the equation,

\frac{310 mL}{523 K} =  \frac{V}{423K}
V = 251 mL
the new volume is 251 mL 
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Needs to be answered ASAP <br><br> What group of protists does Euglena belong to? Why?
Korvikt [17]
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