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german
4 years ago
15

Which of the following particles are free to drift in metals?

Chemistry
1 answer:
Nostrana [21]4 years ago
8 0

Answer:

Electrons

Explanation:

"This free-floating collection of electrons gives metals many of their unique properties, and is sometimes called a “sea of electrons,”

Learn more about it at this website:

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=3&cad=rja&uact=8&ved=2ahUKEwjUw9Sbl7nmAhWQKs0KHXFGCakQFjACegQICxAK&url=https%3A%2F%2Futexaslearn.instructure.com%2Fcourses%2F2010099%2Fpages%2Fexplain-i-metallic-bonding-and-properties-2&usg=AOvVaw3B0fp0MY7ut9ssl_ebAgP7

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How are atomic nuclei developed​
mezya [45]

Answer:

An atom is composed of a positively-charged nucleus, with a cloud of negatively-charged electrons surrounding it, bound together by electrostatic force. ... Protons and neutrons are bound together to form a nucleus by the nuclear force.

8 0
4 years ago
In 1993 the Minnesota Department of Health set a health risk limit for chloroform in groundwater of 60.0 g/L Suppose an analytic
tangare [24]

Answer:

4.74 × 10³ mg

Explanation:

Given data

  • Health risk limit for chloroform in groundwater: 60.0 g/L
  • Volume of the sample of groundwater: 79.0 mL = 79.0 × 10⁻³ L

The maximum mass of chloroform that there could be in the sample of groundwater to meet the standards are:

79.0 × 10⁻³ L × 60.0 g/L = 4.74 g

1 gram is equal to 10³ milligrams. Then,

4.74 g × (10³ mg/1 g) = 4.74 × 10³ mg

6 0
3 years ago
Question 5 (1 point)
ollegr [7]

Answer:

0.00125 moles H₃X

Solution and Explanation:

In this question we are required to calculate the number of moles of triprotic acid neutralized in the titration.

Volume of NaOH used = final burette reading - initial burette reading

                                      = 39.18 ml - 3.19 ml

                                      = 35.99 ml or 0.03599 L

Step 1: Moles of NaOH used

Number of moles = Molarity × Volume

Molarity of NaOH = 0.1041 M

Moles of NaOH = 0.1041 M × 0.03599 L

                          = 0.00375 mole

Step 2: Balanced equation for the reaction between triprotic acid and NaOH

The balanced equation is;

H₃X(aq) + 3NaOH(aq) → Na₃X(aq) + 3H₂O(l)

Step 3: Moles of the triprotic acid (H₃X used

From the balanced equation;

1 mole of the triprotic acid reacts with 3 moles of NaOH

Therefore; the mole ratio of H₃X to NaOH is 1 : 3.

Therefore;

Moles of Triprotic acid = 0.00375 mole ÷ 3

                                     = 0.00125 moles

Hence, moles of triprotic acid neutralized during the titration is 0.00125 moles.

3 0
4 years ago
A brass metal bar is made up of copper and zinc. (Between 50% to 70% is copper.) A brass metal bar weighs 20.15 ounces. 35% of t
dexar [7]

Answer:

The correct answer would be - 13.0975 ounces.

Explanation:

We know that brass is made up of zinc and copper. The copper part of the brass is approximately around 50 to 70% and the remaining is the zinc part.

Given:

Zinc percentage in a brass = 35%

copper percentage would be - 65% (100 - 35 = 65)

Weight of the brass metal bar = 20.15 ounce

ounces of copper are in the bar = ?

Solution:

The weight of the copper in the brass metal in ounces-

= weight of brass* percentage of copper/100

= 20.15*65/100

= 13.0975 ounces of copper.

2nd method =

The weight of the zinc in the brass metal in ounces-

= weight of brass* percentage of zinc/100

= 20.15*35/100

= 7.0525

The weight of the copper = total weight - weight of zinc

= 13.0975 ounces of copper.

6 0
3 years ago
Help me! :> i need help badlyyy
Alexxandr [17]

Answer:

Explanation:

s

3 0
3 years ago
Read 2 more answers
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