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3 years ago

15

Which of the following particles are free to drift in metals?

1 answer:

Nostrana [21]3 years ago

8 0

Answer:

Electrons

Explanation:

"This free-floating collection of electrons gives metals many of their unique properties, and is sometimes called a “sea of electrons,”

Learn more about it at this website:

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=3&cad=rja&uact=8&ved=2ahUKEwjUw9Sbl7nmAhWQKs0KHXFGCakQFjACegQICxAK&url=https%3A%2F%2Futexaslearn.instructure.com%2Fcourses%2F2010099%2Fpages%2Fexplain-i-metallic-bonding-and-properties-2&usg=AOvVaw3B0fp0MY7ut9ssl_ebAgP7

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How many moles of brcl form when 2.74 mol cl2 react with excess br2?

egoroff_w [7]

Following reaction arise between Br2 and Cl2

Br2 + Cl2 → 2BrCl
(1mole) (1mole) (2moles)

From above balanced reaction, it can be seen that 1 mole of Br2 reacts with 1 mole of Cl2 to form 2 mole of BrCl

Thus, when <span>2.74 mol Cl2 reacts with excess Br2, 2.74 X 2 = 5.48 moles of BrCl will be formed. </span>

5 0

3 years ago

How many moles of Ca atoms are in 1 mol of CaSO4?

Galina-37 [17]

Answer:

6.02 x 10²³ atoms

Explanation:

Given parameters:

Number of moles CaSO₄ = 1 mole

Unknown:

Number of Ca atoms in the given compound = ?

Solution:

The given compound is:

CaSO₄

1 mole of CaSO₄ is made up of 1 mole of Ca atoms

Now;

1 mole of any substance contains 6.02 x 10²³ atoms

1 mole of Ca atoms will also contain 6.02 x 10²³ atoms

7 0

3 years ago

if an element [x] contains 8 protons, 8 neutrons and 8 electrons, the atomic number of the element is ?

Kaylis [27]

Answer:

8

Explanation:

The atomic number refers to the number which identifies the element, which is the proton number.

7 0

3 years ago

Your sick puppy is diagnosed with roundworms. They grow inside of the puppy. What type of symbiotic relationship do the puppy an

Ratling [72]

D. Parasitism , the roundworm benefits from the relationship, but the puppy is harmed

4 0

3 years ago

A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago