<u>Answer</u>:
"The arrangement of atoms or ions in a crystal " is described by the terms body-centered cubic and face-centered cubic.
<u>Explanation</u>:
Face centred cubic system explains the crystal structure where an atom is present at each cubic corner of the crystal and the centre of each cube face. Meaningfully, a closed packed plane where at each "face of the cube" atoms touch the alongside face diagonals.
Whereas in body centric cube system has the lattice point present at the 8 corners of cell and an additional one at the center of the cell. Thus, both explains how the atom or ions are placed or arranged in a crystal.
Answer:
removing the Cl₂ as it is formed
.
adding more ICl(s)
.
removing some of the I₂(s).
Explanation:
<em>Le Châtelier's principle </em><em>states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>
<em />
<u>1) Decreasing the volume of the container:</u>
- Decreasing the volume of the container will increase the pressure.
- When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has no moles of gases and the products side (right) has 1.0 mole of gases.
- So, increasing the pressure will shift the reaction to the side with lower moles of gas (left side) and so the total amount of Cl₂ produced is decreased.
so, decreasing the volume of the container will decrease the total amount of Cl₂ produced.
<u>2) Removing the Cl₂ as it is formed:</u>
- Removing Cl₂ gas will decrease the concentration of the products side, so the reaction will be shifted to the right side to suppress the decrease in the concentration of Cl₂ gas by removing and so the total amount of Cl₂ produced is increased.
so, removing the Cl₂ as it is formed will increase the total amount of Cl₂ produced.
<u><em>3) Adding more ICl(s)
:</em></u>
- Adding ICl(s) will increase the concentration of the reactants side, so the reaction will be shifted to the right side to suppress the increase in the concentration of ICl(s) by addition and so the total amount of Cl₂ produced is increased.
so, adding more ICl(s) will increase the total amount of Cl₂ produced.
<u>2) Removing some of the I₂(s):</u>
- Removing I₂ gas will decrease the concentration of the products side, so the reaction will be shifted to the right side to suppress the decrease in the concentration of Cl₂ gas by removing and so the total amount of Cl₂ produced is increased.
so, removing some of the I₂(s) will increase the total amount of Cl₂ produced.
<em>the following changes will increase the total amount of of Cl2 that can be produced:</em>
- removing the Cl₂ as it is formed
.
- removing some of the I₂(s).
The density of a plasma can be described as : ( A ) Low density
<h3><u>Density </u></h3>
Density is the mass per unit volume of a substance, it is used for comparison between substances because the mass and volume which are scalar quantities of substances are applied.
The density of plasmas are low when compared to solids because the volume occupied by a plasma of the same mass as a solid, is greater when compared to the volume occupied by a solid.
Hence we can conclude that The density of a plasma can be described as Low density.
Learn more about density : brainly.com/question/6838128
Number of moles is (actual mass)/(molar mass)
So there are 10.37/25.94 mols
So there are 0.3998 (or 0.4) moles
Answer: 50%
Explanation:
The number of electron pairs are 2 for hybridization to be 
and the electronic geometry of the molecule will be linear.
1. percentage of s character in sp hybrid orbital =
2. percentage of s character in 
hybrid orbital =
3. percentage of s character in 
hybrid orbital =
Thus percentage of s-character in an sp hybrid is 50%.
