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3 years ago

8

For a given recipe, 8 cups of flour are mixed with 4 cups of sugar. How many cups of flour should be used if 6 cups of sugar are

used?

1 answer:

Vedmedyk [2.9K]3 years ago

4 0

Answer:

12 cups of flour

Step-by-step explanation:

if 8 cups of flour=4 cups of sugar what about 6 cups of sugar.you cross multiply.

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A Tv show had 3.5x10 to the 6th power viewers for their first episode and 8.5x10 to the 6th power viewers for their second episo

Sonbull [250]

is that x a variable or multiplication symbol?

Step-by-step explanation:

if multiplication the answer is 12 • 10 to the 6th power or 12,000,000 they are the same

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3 years ago

A gram is equivalent to 0.0353 ounces. One ounce is how many grams? Round to the nearest tenth.

Artemon [7]

Answer:

Your answer is 28.3495

Brainliest is appreciated

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3 years ago

Read 2 more answers

A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude

EleoNora [17]

Answer:

a) $P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)$

And we can use the probability mass function and we got:

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

And adding we got:

$P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061$

b) $P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182$

c) $P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]$

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

$P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054$

And replacing we got:

$P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886$

d) $E(X) = 20*0.2= 4$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=20, p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

We want this probability:

$P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)$

And we can use the probability mass function and we got:

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

And adding we got:

$P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061$

Part b

We want this probability:

$P(X=4)$

And using the probability mass function we got:

$P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182$

Part c

We want this probability:

$P(X>3)$

We can use the complement rule and we got:

$P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]$

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

$P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054$

And replacing we got:

$P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886$

Part d

The expected value is given by:

$E(X) = np$

And replacing we got:

$E(X) = 20*0.2= 4$

3 0

3 years ago

Write an equation of the line that passes

arsen [322]

Y= 3x - 20 is an equation parallel to y=3x-3 and passes through (6,-2).

4 0

3 years ago

A plane traveled 2565 miles with the wind in 4.5 hours and 2205 miles against the wind in the same amount of time. Find the spee

kherson [118]

Answer:

plane: 530 mi/h
wind: 40 mi/h

Step-by-step explanation:

Let p and w represent the speeds of the plane and the wind. The relation between time, speed, and distance is ...

speed = distance/time

p +w = (2565 mi)/(4.5 h) = 570 mi/h

p -w = (2205 mi)/(4.5 h) = 490 mi/h

Adding these speeds, we get ...

(p +w) +(p -w) = (570) +(490) mi/h

2p = 1060 mi/h

p = 530 mi/h

Then the speed of the wind is ...

w = 570 mi/h -p = (570 -530) mi/h = 40 mi/h

The plane's speed is 530 mi/h; the wind speed is 40 mi/h.

7 0

2 years ago