Answer:
t = 1.107
Step-by-step explanation:
Finding the solution using derivatives involves finding the lower zero of the quadratic that is the second derivative of the given function. That second derivative will be ...
f''(t) = 12(1.6714)t^2 -6(22.45)t +2(62.27)
= 20.0568t^2 -134.7t +124.54
= 20.0568(t -3.35796)² -101.619 . . . . rewrite to vertex form
Then f''(t) = 0 when ...
t ≈ 3.35796 -√(101.619/20.0568) ≈ 1.10706
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The solution is perhaps more easily found using a graphing calculator to find the peak of the first derivative. (See attached.) It tells us ...
t ≈ 1.107
1.1 years after the beginning of 1998 is about 1.2 months into 1999.
Rents were increasing most rapidly in early February of 1999.
Answer:
C) Both
Step-by-step explanation:
The given equation is:

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.
Using this property:

So, Erik's solution strategy would work.
Now, let us discuss about Caleb's solution strategy:
Multiply
i.e.
= 
So, the equation becomes:

Comparing this equation to standard quadratic equation:

a = 3, b = -10, c = -8
So, this can be solved using the quadratic formula.


The answer is same from both the approaches.
So, the correct answer is:
C) Both
Jack --> 440 = rate * 88Jack --> 5 yrds/sex = rateJack in 55 seconds --> distance = 5 * 55 = 275 yrds440 - 275 = 165 yards handicap.
Answer:
Compount interest earns more. Difference between 2 interest is $92 445.39
Step-by-step explanation:
Simple Interest:

p = $10000
r = 3%
t = 2years
I = (10000×3×2)/100
= $600
Total amount = $10 600
Compound Interest:

p = $100000
r = 3/730 (daily)
t = 730 (2yrs)
A = 100000[1+(3/73000)]^730
= $103 045.39 (2d.p)
Difference = $103045.39 -
$10600
= $92 445.39
(Correct me if i am wrong)
√50 lies between 7 and 8.