Question

Helppp No links plzzz I’m way behind in classs

Answer 1

Answer:

$\frac{3x^3z^5}{5y}$ ( $\frac{20y^3}{x^2z^6}$)

Step-by-step explanation:

When given the following equation,

$\frac{3x^3z^5}{5y}$ ÷ $\frac{x^2z^6}{20y^3}$

The first step is to convert the equation into a form that can be solved, in essence dividing any number by a fraction is the same as multiplying that number by the reciprocal of the fraction. The reciprocal of a fraction is when one switches the position of the numerator and denominator, the numerator is the number on top of the fraction, and the denominator is the number underneath the fraction.

$\frac{3x^3z^5}{5y}$ ÷ $\frac{x^2z^6}{20y^3}$

$\frac{3x^3z^5}{5y}$ * $\frac{20y^3}{x^2z^6}$

Simplify, reduce the numbers that are found in common between the numerator and denominator,

$\frac{3x^3z^5}{5y}$ * $\frac{20y^3}{x^2z^6}$

$\frac{3x^3z^5*20y^3}{5y*x^2z^6}\\\\=\frac{3x*4y^2}{z}\\\\=\frac{12y^2x}{z}$

Answer 2

Answer:

Step-by-step explanation:

option c is correct

if u change the divide sign into multiplication then always do its reciprocal.