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3 years ago

Solve the following equation: x + 25 = 30

Mathematics

2 answers:

babymother [125]3 years ago

7 0

Answer:

X + 25 = 30

X + 25-25 = 30 - 25 = 5

Step-by-step explanation:

cricket20 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

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Find x,y, and z and please show all work.

lana [24]

Answer:

x = 47°

y = 10

z = 5

Step-by-step explanation:

They share the middle line which is one side. It's given that side y is congruent to the side with a value of 5. Angle X and the non labeled angel are also congruent to each other. Using SAS (side angle side) we can conclude the 2 triangles are congruent, which means all angles and sides are congruent and equal.

The angles of a triangle add to 180.

x+90+43=180

x=47

z is congruent/equal to 5 since they are congruent and equal triangles. Therefore z=5

Y is congruent to side 10, which also means it is equal to 10. Therefore y=10

6 0

3 years ago

I'm not exactly sure how to solve this or what the answer is.

arlik [135]

Answer:

9x^2-49

Step-by-step explanation:

FOIL

8 0

3 years ago

The two short sides of a triangle are 3 and 4 inches. what is the length of the hypotenuse,in inches?

disa [49]

Answer:

The length of the hypotenuse is 5 inches.

Step-by-step explanation:

The formula for finding the hypotenuse is $a^{2} + b^{2} = c^{2}$ ,

with a and be being the two shorter sides of the triangle, while c is the hypotenuse.

Let's plug in our values for a and b and solve.

$4^{2} + 3^{2} = c^{2}$

16 + 9 = $c^{2}$

25 = $c^{2}$

What is the square root of 25? 5.

The length of the hypotenuse is 5 inches.

3 0

3 years ago

Read 2 more answers

How would you solve this? help.

Eddi Din [679]

Answer:

Center: (3,3)

Radius: $2\sqrt{5}$

Step-by-step explanation:

Midpoint and Distance Between two Points

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

The distance between both points is given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

$\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3$