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Minchanka [31]
2 years ago
11

The minimum wage in 2003 was $5.15. This was W more than the minimum wage in 1996. Write an expression for the minimum wage in 1

996.
Mathematics
2 answers:
kotegsom [21]2 years ago
8 0
It will be 5.15-w= minimum wage in 1996. Your keyword in that word problem would be when they said that 5.15 was w more than the minimum wage in 1996. I hope I helped ya :)
Zina [86]2 years ago
8 0

Answer:

Expression for the minimum wage in 1996 is:

5.15-W

Step-by-step explanation:

The minimum wage in 2003 was W more than the minimum wage in 1996.

Minimum wage in 2003=Minimum wage in 1996+W

The minimum wage in 2003 was $5.15.

Let x be the minimum wage in 1996.

Then, 5.15=x+W

x=5.15 - W

Hence, expression for the minimum wage in 1996 is:

5.15-W

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<img src="https://tex.z-dn.net/?f=%28-5x%5E3%29%5E3%2F%2810x%5E5%29%5E2" id="TexFormula1" title="(-5x^3)^3/(10x^5)^2" alt="(-5x^
marta [7]

Answer:

-\frac{5}{4x}

Step-by-step explanation:

<h2>\left(-5x^3\right)^3\div \left(10x^5\right)^2</h2><h2>\frac{-5^3x^9}{\left(10x^5\right)^2}</h2><h2>\frac{-5^3x^9}{10^2x^{10}}</h2><h2>\frac{-5^3x^9}{5^2\cdot \:2^2x^{10}}</h2><h2>\frac{-5x^9}{2^2x^{10}}</h2><h2>\frac{-5}{2^2x}</h2>

-\frac{5}{4x}

- hope it helps! -

<h2 />

3 0
1 year ago
......................................
Julli [10]
Lol hiiiiiiiiiiiiiiiiii
7 0
2 years ago
Please help asap!!!
sp2606 [1]

Answer:

y=\frac{1}{6} (x+5)^2-4.5

y=\frac{-1}{20} (x-10)^2+1

Step-by-step explanation:

focus at (-5, -3), and directrix y = -6

Directrix y=-6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

(h,k) is the center

P is the distance between focus and vertex

distance between focus and directrix = 2p

distance between -3  and y=-6 is 3

2p = 3

p = 3/2 or p = 1.5

Focus is (h, k+p)

given focus is (-5, -3) so h= -5  and k+p = -3

k+p=-3, plug in 1.5 for p

k + 1.5 = -3

subtract 1.5 on both sides

k = -4.5

(x-h)^2 = 4p(y-k)

(x+5)^2= 4(1.5) (y+4.5)

(x+5)^2= 6(y+4.5)

divide by 6 on both sides

then subtract 4.5 on both sides

y=\frac{1}{6} (x+5)^2-4.5

focus at (10, -4), and directrix y = 6.

Directrix y=6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

distance between focus and directrix = 2p

distance between -4  and y=6 is -4-6=-10

2p = -10

p = -5

Focus is (h, k+p)

given focus is (10, -4) so h= 10  and k+p = -4

k+p=-4, plug in 5 for p

k - 5 = -4

add 5 on both sides

k = 1

(x-h)^2 = 4p(y-k)

(x-10)^2= 4(-5) (y-1)

(x-10)^2= -20(y-1)

divide by -20 on both sides and add 1 on both sides

y=\frac{-1}{20} (x-10)^2+1


8 0
2 years ago
A triangle has side lengths 1, 2 and square cute of 3. The triangle
seraphim [82]
A, I hope this helps!
6 0
2 years ago
Read 2 more answers
the probability of a radar station detecting an enemy plane is 62%. if 50 stations are in use what is the probability of exactly
podryga [215]
This is binomial probability with n=50 and p=0.62.

We want binom(50,0.62,35).

One way to calculate this is to use a calculator with statistical functions.

My TI-83 Plus turned out the result 0.061.
7 0
3 years ago
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