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Minchanka [31]
3 years ago
11

The minimum wage in 2003 was $5.15. This was W more than the minimum wage in 1996. Write an expression for the minimum wage in 1

996.
Mathematics
2 answers:
kotegsom [21]3 years ago
8 0
It will be 5.15-w= minimum wage in 1996. Your keyword in that word problem would be when they said that 5.15 was w more than the minimum wage in 1996. I hope I helped ya :)
Zina [86]3 years ago
8 0

Answer:

Expression for the minimum wage in 1996 is:

5.15-W

Step-by-step explanation:

The minimum wage in 2003 was W more than the minimum wage in 1996.

Minimum wage in 2003=Minimum wage in 1996+W

The minimum wage in 2003 was $5.15.

Let x be the minimum wage in 1996.

Then, 5.15=x+W

x=5.15 - W

Hence, expression for the minimum wage in 1996 is:

5.15-W

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7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54} simplified as 11\sqrt{3}- 7\sqrt{6} or 1.909 .

<u>Step-by-step explanation:</u>

We need to Simplify seven square root of three end root minus four square root of six end root plus square root of forty eight end root minus square root of fifty four. Which is equivalent to 7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54} :

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