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Minchanka [31]
3 years ago
11

The minimum wage in 2003 was $5.15. This was W more than the minimum wage in 1996. Write an expression for the minimum wage in 1

996.
Mathematics
2 answers:
kotegsom [21]3 years ago
8 0
It will be 5.15-w= minimum wage in 1996. Your keyword in that word problem would be when they said that 5.15 was w more than the minimum wage in 1996. I hope I helped ya :)
Zina [86]3 years ago
8 0

Answer:

Expression for the minimum wage in 1996 is:

5.15-W

Step-by-step explanation:

The minimum wage in 2003 was W more than the minimum wage in 1996.

Minimum wage in 2003=Minimum wage in 1996+W

The minimum wage in 2003 was $5.15.

Let x be the minimum wage in 1996.

Then, 5.15=x+W

x=5.15 - W

Hence, expression for the minimum wage in 1996 is:

5.15-W

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Split the triangle into a 30-60-90 triangle. Since you have LM from that triangle, you can figure out the other sides. Then, using the leg from that triangle, the one next to it is a 45-45-90 triangle, meaning it's isosceles.

KM = 30 + 10√3

KL = 10√6

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How do you find the area of a triangle?
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Evaluate for x=2 and y=3: x^2y^-3/x^-1y
Artemon [7]

Answer:

8/81

Step-by-step explanation:

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The given expression reduces to x³ / y^4.

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4 0
3 years ago
Un cono ha l'area laterale di 255 pigreco cm^2, l'apotema di 17 cm e pesa 900 pigreco g. Calcola il peso specifico del materiale
valkas [14]

Answer:

The specific weight is 1.5\frac{g}{cm^{3}}

Step-by-step explanation:

The question in English

A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed

step 1

Find the radius of the cone

we know that

The lateral area of a cone is equal to

LA=\pi rl

we have

LA=255\pi\ cm^{2}

l=17\ cm

substitute the values

255\pi=\pi r(17)

Simplify

255=r(17)

r=255/(17)=15\ cm

step 2

Find the height of the cone

Applying the Pythagoras Theorem

l^{2} =r^{2} +h^{2}

substitute the values and solve for h

17^{2} =15^{2} +h^{2}

h^{2}=17^{2}-15^{2}

h^{2}=64

h=8\ cm

step 3

Find the volume of the cone

The volume of the cone is equal to

V=\frac{1}{3}\pi r^{2}h

substitute the values

V=\frac{1}{3}\pi (15)^{2}(8)

V=600\pi\ cm^{3}

step 4

Find the specific weight

Divide the mass by the volume

\frac{900\pi }{600\pi}=1.5\frac{g}{cm^{3}}

4 0
3 years ago
Pls help me i dont care if u get it wrong it wont bother me but pls help me :/
Naddika [18.5K]

Answer:

3; 6; 9; 12; 15; 18;

Step-by-step explanation:

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3*2=6

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3 years ago
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