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JulijaS [17]
3 years ago
5

Given a PrintWriter reference variable named output that references a PrintWriter object, write a statement that writes the stri

ng "Hello, World" to the file in to which output streams.
Computers and Technology
1 answer:
Nadya [2.5K]3 years ago
4 0

Answer:

A PrintWriter reference variable named output that references a PrintWriter object is as follows:

//PrintWriter output = new PrintWriter(outfile);

PrintWriter output = new PrintWriter("output.txt");

The statement that writes the string "Hello World" to the file output is as follows:

//output.print(message)

output.print("Hello World");

Explanation:

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Waterfall model and spiral model are used in software development life cycle or SDLC. Any software development process follows one of these models depending on the type of software and the requirements of the customer.

Waterfall model

This model is called as sequential model since it works in stages. The output of first stage becomes the input of the second stage.

The errors of the first stage can be rectified only when it is completed. This is time consuming and makes the process lengthy. Stage 1 is completed before stage 2 begins.

The six stages involved in waterfall model are Requirement Gathering and analysis, System Design, Implementation, Integration and Testing, Deployment of system, and Maintenance.

Spiral model

This model is implemented in iterations. It is also called evolutionary model.  

Initially a prototype of the system is prepared. Then, it is followed by development of small parts of the system.

These smaller parts are then assembled to produce the final system.

The four stages which form the spiral model are Identification, Design, Development and Evaluation and Risk Analysis.

The differences between the two models are summarized below.

1. Waterfall model works in linear method. Spiral model follows evolutionary method.

2. Errors and risks are discovered/ rectified after the stage is over. Errors and risks are discovered/ rectified earlier.

3. Waterfall model is suitable for small projects. Spiral model is suitable for large projects.

4. Requirements identification and planning is the initial stage in the waterfall model. Requirements identification and planning is done when needed, in the spiral model.

5. Waterfall model allows little to no flexibility in the system. Spiral model allows flexibility in the system.

6. Low flexibility makes the waterfall model more risky. High flexibility makes the spiral model less risky.

7. Waterfall model, overall, takes less time since requirements are clear. Spiral model is implemented when the requirements of the system are not clear and become clear through prototypes.

8 0
3 years ago
During data declaration, a name is binded to a memory location, what else can be identify as part of this process?
igomit [66]

data declaration means a variable which contain data value and it can be declared as integer, float, character, double, boolean (data types).

example:

int r;

char name;

float g;

double k= 23.34;

5 0
3 years ago
Propose a data structure that supports the stack push and pop operations and a third operation findMin, which returns the smalle
juin [17]

Answer: attached below

Explanation:

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3 years ago
To celebrate earth day, the employees of a company plan to reduce their carbon footprint in the workplace. Identify the changes
andrew11 [14]
<span>Go paperless. 
Use natural lighting. 
Grow trees nearby. 
Reduce, reuse, and recycle. 
Carpool. 
</span>
5 0
3 years ago
Read 2 more answers
Define a structure Triangle that contains three Point members. Write a function that computes the perimeter of a Triangle . Writ
qwelly [4]

Answer:

The program in C++ is as follows:

#include <iostream>    

using namespace std;

int perimeter(int side1, int side2, int side3){

return side1+side2+side3;

}

struct Triangle  {

int side1;  int side2;   int side3;

};

int main(void) {

int side1, side2, side3;

cout<<"Sides of the triangle: ";

cin>>side1>>side2>>side3;

struct Triangle T;

T.side1 = side1;

T.side2 = side2;

T.side3 = side3;  

cout << "Perimeter: " << perimeter(T.side1,T.side2,T.side3) << endl;

return 0;

}

Explanation:

See attachment for complete code where comments are as explanation

Download cpp
7 0
3 years ago
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