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3 years ago

Rewrite 2/5 + 5/12 with a common denominator.

Mathematics

2 answers:

gtnhenbr [62]3 years ago

5 0

Answer: 60

Step-by-step explanation:

2/5 + 5/12 first we need to make the denominators the same, the least common denominator with 12 and 5 is 60

the overall answer for 2/5 + 5/12 is 49/60

RoseWind [281]3 years ago

4 0

Answer:60 is the common denominator

Step-by-step explanation:

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Examine the linear equation. 8x – y = –6 Choose the slope-intercept form of the equivalent equation:

alexdok [17]

Step-by-step explanation:

The slope-intercept form can be obtained by solving for y.

8x-y=-6

-8x

-y=-8x-6

divide by negative 1 to turn y positive.

y=8x+6

6 0

3 years ago

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Caleb bought groceries and paid

lutik1710 [3]

Answer:

Price of Caleb's groceries before tax= $6.4

Step-by-step explanation:

Let price of groceries before tax be = $ $x$

Sales tax % = 2.5%

Sales tax applied = $2.5\% \ of\ x = \frac{25}{100}\times x = \frac{25}{100} x$

Actual sales tax paid = $1.60

∴ $\frac{25}{100}x=1.60$

Multiplying both sides by 100.

$100\times \frac{25}{100}x=1.60\times 100$

$25x=160$

Dividing both sides by 25.

$\frac{25x}{25}=\frac{160}{25}$

$x=6.4$

∴ Price of groceries before tax= $6.4

8 0

4 years ago

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at a particular school 50% of students travel by bus. if this represents 600 children how many children attend the school

hichkok12 [17]

Answer:

1200 students at the school

Step-by-step explanation:

Let x be the total number of students at the school

50% ride the bus

600 students ride the bus

x*50% = 600

Changing to decimal form

.50x = 600

Divide each side by .5

.50x/.5 = 600/.5

x =1200

1200 students at the school

4 0

3 years ago

Read 2 more answers

Can somebody fill in the blanks for me.

alukav5142 [94]

Answer:

Step-by-step explanation:

2: exterior and opposite

3:supplementary

5: angles and equal

6: supplementary

4 0

3 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

3 years ago