Answer:
0.0008 mole of HCl
Explanation:
From the balanced equation between HCl and NaOH:
1 mole of acid requires 1 mole of base for neutralization.
mole = molarity x volume
mole of NaOH = 0.02 x 0.04 = 0.0008 mole
mole HCl = 0.16 x 0.01 = 0.0016 mole
Since 1 mole of NaOH requires 1 mole of HCl for neutralization, it means that 0.0008 mole of NaOH will require 0.0008 mole of HCl. The remaining mole of HCl must have been neutralized by the antiacid:
0.0016 - 0.0008 = 0.0008 mole.
Therefore, 0.0008 mole of HCl must have been neutralized by the antiacid.
5.2/ 24.3 = 0.214
0.214 x 2 = 0.428
0.428 x 36.5= 15.6g
In order to find out the number of electrons present in s orbital of Phosphorous we have to write the electronic configuration of phosphorous.
As the Atomic number of Phosphorous is 15 so it will have 15 electrons in neutral state. So,
P = 15 = 1s², 2s², 2p⁶, 3s², 3p³
Now analyzing electronic configuration, we found that it contains 3 s orbitals, i.e. 1s, 2s and 3s, and each s orbital is completely filled with two electrons each.
Result:
Therefore, a total of six electrons are present in all s orbitals of neutral Phosphorous Atom.
The given equilibrium reaction is,
According to Le Chatelier's principle states that when a system in equilibrium is disturbed by varying conditions like concentration, pressure, and temperature of the system, the system tries to counter act the affect by shifting the equilibrium towards the required side.
When 
is removed from the system, the concentration of chlorine () decreases, the equilibrium is disturbed. So, the system tries to re-establish the equilibrium by moving in that direction which produces more of chlorine, that is towards the reactant side.
The correct answer would be: 1. reaction would go to the left, making more "reactants"
Answer:
#2
C2H4 + 3O2 ----> 2CO2 + 2H2O
#3
2FeBr3 + 3H2SO4 ----> Fe2(SO4)3 + 6HBr
#4
2Al + 3F2 -----> 2AlF3
Explanation:
