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Elis [28]
3 years ago
9

The modern view of an electron orbital in an atom is best described as

Chemistry
1 answer:
Mrrafil [7]3 years ago
5 0

invisable

you probably dont want to put that...

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Solve the equation 5m+4=7m+6​
ioda
The equation of 5m+4=7m+6 is equal to m=-1
7 0
3 years ago
Calculate the silver ion concentration in a saturated solution of silver(i) sulfate (ksp = 1.4 × 10–5).
deff fn [24]

Answer:

= 0.030 M

Explanation:

We can take x to be the concentration in mol/L of Ag2SO4 that dissolves  

Therefore;  concentration of  Ag+ is 2x mol/L and that of SO4^2- x mol/L.

Ksp = 1.4 x 10^-5

Ksp = [Ag+]^2 [SO42-]

      = (2x)^2(x)

      = 4x^3  

Thus;

4x^3  = 1.4 x 10^-5

         = 0.015 M

molar solubility = 0.015 M

But;

[Ag+]= 2x

Hence; silver ion concentration is

= 2 x 0.015 M

= 0.030 M

6 0
3 years ago
This equation shows a ____ refer to this summary equation of photosynthesis to complete the sentences about chemical bonds and r
coldgirl [10]

The balanced chemical equation representing the process of photosynthesis is:

6 CO_{2} +12H_{2}O-->C_{6}H_{12}O_{6}+6O_{2}

The reactants in the process of photosynthesis are CO_{2}and HH_{2}O and the products of the reaction are glucose C_{6}H_{12}O_{6} and oxygen O_{2}. Oxygen is the nonpolar covalent gas which is released in the process of photosynthesis. The reactant CO_{2} is a nonpolar covalent gas while the other reactant waterH_{2}O has polar covalent O-H bonds.

In the balanced chemical equation, the number of each type of element must be equal on both sides of the reaction.

6 0
3 years ago
3 waves are shown with a line through their center. The bottom of the first wave is labeled C. A bracket labeled D connects the
Likurg_2 [28]

Answer:Label the parts of this wave.

A:  

✔ crest

B:  

✔ amplitude

C:  

✔ trough

D:  

✔ wavelength

Explanation:

8 0
3 years ago
Read 2 more answers
2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X 10^{23}

from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

from the relation:

number of moles = \frac{mass}{atomic mass of 1 mole}

rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

thus, 3.47 x 10^{23} atoms of gold have mass of 113.44 grams

3 0
3 years ago
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