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KonstantinChe [14]
3 years ago
7

Given the chemical equation: Fe2O3 + 3CO --> 2Fe + 3CO2

Chemistry
1 answer:
lapo4ka [179]3 years ago
6 0

Answer:

The answer to your question is 160 g of Fe₂O₃  

Explanation:

Data

mass of Fe = 112 g

mass of CO = in excess

mass of Fe₂O₃ = ?

Balanced chemical reaction

                Fe₂O₃  +  3CO  ⇒  2Fe  +  3CO₂

Process

1.- Calculate the molar mass of Fe₂O₃ and Fe

Molar mass Fe₂O₃ = (56 x 2) + (16 x 3) = 112 + 48 = 160 g

atomic mass of Fe = 56

2.- Use proportions to calculate the mass of Fe₂O₃ needed

                160 g of Fe₂O₃ ------------------- 2(56) g of Fe

                 x     g of Fe₂O₃ ------------------ 112 g of Fe

                 x = (112 x 160) / 2(56)

                 x = 17920/112

                 x = 160 g of Fe₂O₃          

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Answer: 0.18 M

Explanation:

Initial molarity, M1 = 0.8 M

Initial olume, V1 = 225 ml

Final volume, V2 = 1000 ml

Final Molarity, M2 = M1V1/V2

= 0.8 x 225/1000

= 0.18 M

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What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?
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6 0
3 years ago
What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
Montano1993 [528]

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

4 0
3 years ago
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