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Crazy boy [7]
3 years ago
13

The circumference of his 72 cm, What is the length of AP (the minor arc)?

Mathematics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

Step-by-step explanation:

It would look like 90 divided by 360 multiplied by the given circumference which is 72 cm.

So 90 / 360 x 72

Simply the fraction above, it will give us:

¼ x 72

So the answer would be 18 cm that is the length of DE (minor arc)

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a cup is 6.4 cm tall, not including the 0.6 cm lip. cups are stacked inside one another. select the function that represents the
Alja [10]

Answer: 20

H(c) = 6.4 + 0.6c

<u>6.4</u> is the constant.

When the height of the cups is <u>18.4</u> the function is:

18.4 = 6.4 + 0.6c

Then, you add <u>6.4</u> from both sides

18.4 - 6.4 + 6.4 = 6.4 + 0.6c - 6.4  + 6.4

Simplify

18.4 = 6.4 + 0.6c

Switch sides

6.4 + 0.6c = 18.4

Multiply both sides by <u>10</u>

6.4 x 10 + 0.6c x 10 = 18.4 x 10

Refine

64 + 6c = 184

Subtract <u>64</u> from both sides

64 + 6c - 64 = 184 - 64

Simplify

6c = 120

Divide both sides by <u>6</u>

6c/6 = 120/6

c = <u>20</u>

8 0
3 years ago
Hugo drove 26 miles on
Sergio [31]

Answer:

70

Step-by-step explanation:

26 times 2 the plus 18 and you get 70 hope this helps

6 0
2 years ago
Read 2 more answers
The new patio at Tonya's house is 5 yards long by 10 feet wide. She is going to cover the patio with square bricks that measure
Klio2033 [76]

Answer:

A

Step-by-step explanation:

Steps to take to determine the answer

  1. Because the length is in yards, it has to be converted to foot
  2. Find the area of the patio using the length and width measured in foot
  3. Determine the area of the square brick
  4. Multiply the cost of the brick by the area

1 yards = 3 foot

5 x 3 = 15 foot

Area of a rectangle = length x breadth

15 x 10 = 150 ft^2

Cost = 150 x 4 = $600

4 0
3 years ago
1. Find the distance from point P to QS
12345 [234]

Answer:

5.7 units

Step-by-step explanation:

The distance from point P to QS is the distance from point P (1, 1) to the point of interception R(-3, 5).

Use distance formula to calculate distance between P and R:

PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

P (1, 1) = (x_1, y_1)

R(-3, 5) = (x_2, y_2)

Plug in the values into the formula.

PR = \sqrt{(-3 - 1)^2 + (5 - 1)^2}

PR = \sqrt{(-4)^2 + (4)^2}

PR = \sqrt{16 + 16}

PR = \sqrt{32}

PR = 5.7 units (to nearest tenth)

4 0
3 years ago
Nina purchased apples and strawberries. She purchased a total of 9 pounds of fruit and spent a total of $16.35. Strawberries cos
irina [24]

Answer:

4 pounds of strawberries and 5 pounds of apples are bought.

Step-by-step explanation:

Given:

Total number of pounds of fruit = 9 pounds

Total money spent = $16.35

Cost of 1 pound of strawberry = $1.60

Cost of 1 pound of apple = $1.99

Let 'x' pounds of strawberries and 'y' pounds of apples are bought.

So, <u><em>as per question:</em></u>

<em>The sum of the pounds is 9. So,</em>

x+y=9\\\\y=9-x----1

Now, total sum of the fruits is equal to the sum of 'x' pounds of strawberries and 'y' pounds of apples. So,

1.60x+1.99y=16.35----2

Now, plug in the 'y' value from equation (1) in to equation (2). This gives,

1.60x+1.99(9-x)=16.35\\\\1.60x+17.91-1.99x=16.35\\\\Combining\ like\ terms, we get:\\\\1.60x-1.99x=16.35-17.91\\\\-0.39x=-1.56\\\\x=\frac{-1.56}{-0.39}=4\ pounds

Now, from equation 1, we have:

y=9-4=5\ pounds

Therefore, 4 pounds of strawberries and 5 pounds of apples are bought.

4 0
2 years ago
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