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atroni [7]
3 years ago
13

What is the most efficient first step to isolate the variable term on one side of this equation? -9x = -4x + 5 A. Subtract 5 fro

m both sides. B. Add 5 to both sides. C. Subtract 9x from both sides. D. Add 4x to both sides.
Mathematics
2 answers:
ehidna [41]3 years ago
6 0

<u>Answer</u>

D. Add 4x to both sides.


<u>Explanation</u>

-9x = -4x + 5

On the right hand side we have -4x. We have to add 4x on both sides to have;

-9x + 4x= -4x + 5 + 4x          

(-4x + 4x = 0)

(-9x + 4x = -5x)

∴ -5x = 5

PSYCHO15rus [73]3 years ago
3 0

For this case we have the following equation:

-9x = -4x + 5

We want to clear x:

For this we must follow a series of steps, the first consists of adding 4x to both sides of the equation to obtain:

-9x + 4x = -4x + 4x + 5\\-5x = 5

In this way, the variable term remains on one side of the equation.

Thus, the first step will be:

Add 4x to both sides

Answer:

Option D


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Answer:

A

Step-by-step explanation:

z = -3 - 5i

z (i) = i (-3 - 5 i)

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z (i) = -3i - 5 (-1)

z (i) = -3i + 5

z (i) = 5 - 3i

Therefore, letter A is the correct answer.

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Which fraction has a terminating decimal as a decimal expansion <br> 1/3<br> 1/5<br> 1/7 <br> 1/9
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The Golden Gate Bridge in San Francisco is 220 feet tall. If a model of the bridge is created with a scale of 3 feet = 80 feet,
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3 years ago
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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
The equation of the line in standard form is...
Rudik [331]

Answer:

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Step-by-step explanation:

here is my work although I am not 100 percent sure I am right because,I am learning the same thing as you

-6+1 over 4+5

y+1=-5/9(x+5)

y+1=-5/9x-25/9

y=-5/9x-16/9

5/9+y=-16/9

5x+9y=-16

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