What is the area of the square

because we set it up like 5w-1= w then subtract the w so it’s on the same side as the other w. then we add the one and divide the one by 4 to get the w by itself. then you plug the ¼ into the equation 12(w) to equal 3!

5 0

2 years ago

The area of a circle is 286 cm2. Use the π button on your calculator for π in your calculations.

hram777 [196]

Answer:

9.54 cm

Explanation:

area = πr^2

286 cm^2= πr^2

=>πr^2= 286 cm^2

=>r^2= 286÷π

=>r= √286÷π

: 9.54. m

circumference=2πr

=> circumference=2×π×9.54

=60 cm

4 0

2 years ago

Assume that 155 students are surveyed and every student takes at least one of the following languages. The results of the survey

balu736 [363]

Answer:

91 people take Russian

26 people take French and Russian but not German

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that take French.

-The set B represents the students that take German

-The set C represents the students that take Russian.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a is the number of students that take only Franch, A \cap B is the number of students that take both French and German , A \cap C is the number of students that take both French and Russian and A \cap B \cap C is the number of students that take French, German and Russian.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following subsets:

$a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)$

There are 155 people in my school. This means that:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 155$

The problem states that:

90 take Franch, so:

$A = 90$

83 take German, so:

$B = 83$

22 take French, Russian, and German, so:

$A \cap B \cap C = 22$

42 take French and German, so:

$A \cap B = 42 - (A \cap B \cap C) = 42 - 22 = 20$

41 take German and Russian, so:

$B \cap C = 41 - (A \cap B \cap C) = 41 - 22 = 19$

22 take French as their only foreign language, so:

$a = 22$

Solution:

(1) How many take Russian?

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$C = c + (A \cap C) + 19 + 22$

$C = c + (A \cap C) + 41$

First we need to find $A \cap C$ , that is the number of students that take French and Russian but not German. For this, we have to go to the following equation: