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soldi70 [24.7K]
3 years ago
10

DOES ANYONE KNOW HOW TO DO THIS????????

Mathematics
1 answer:
castortr0y [4]3 years ago
4 0

Answer:

1. figure 4

2. Figure 1

3. Figure 3

Step-by-step explanation:

1. r is the degree of the line or group of dots that makes a line. for r=1, the line is going to be as close to a linear line as possible. the dots will be close together a make either a close or perfect straight line. This is why we pick figure 4, because the points are decently close together and form a positive slope.

2. a linear relationship can be tested by a straight line test, and in this case you pick the figure that fails the test the most. in this case, Figure 1 fits.

3.  looking for r=-1 is looking for the opposite of r=1, so since figure 3 is the opposite of figure 4, we know it fits the description

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Find the slope of the line through the given points
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Ira Lisetskai [31]

Solution: The factor form of the given polynomial is f(x)=(x+4)(x+3)(x+2)(x+1).

Explanation:

To find the factor form of the given polynomial fisrt find the random value of x for which the vlaue of f(x) is 0.

The value of the function f(x) is 0 for x=-1, therefore (x+1) is a factor of given function.

Use synthetic method to divide the given polynomial for by (x+1). Write coefficients of polynomial in top line and -1 on left side of the line. Write first element in bottom line then multiply it by -1 and write it in second line below the element second element and the add. The division by synthetic method is given in figure 1.

The bottom line shows the coefficients of the quotient polynomial.

So f(x)=(x+1)(x^3+9x^2+26x+24)

Similarly (x+2) is the factor of given polynomial because for x=-2 the value of parenthesis polynomial is 0.

Use synthetic method to divide the parenthesis polynomial for by (x+2). it is shown in figure 2.

So

f(x)=(x+1)(x+2)(x^2+7x+12)\\f(x)=(x+1)(x+2)(x^2+3x+4x+12)\\f(x)=(x+1)(x+2)(x(x+3)+4(x+3))\\f(x)=(x+1)(x+2)(x+3)(x+4)

Hence the factor form of the given polynomial is f(x)=(x+4)(x+3)(x+2)(x+1). The graph of the given function is given in figure 3.


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