The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.
A plane that travels a distance
, in kilometers, with a bearing of
sexagesimal degrees can be represented in standard position by means of the following expression:
(1)
We can obtain the resulting vector (
) by the principle of superposition:
(2)
If we know that
,
,
,
,
and
, then the resulting vector is:

![\vec R = (5\sqrt{3}, 6) \,[km]](https://tex.z-dn.net/?f=%5Cvec%20R%20%3D%20%285%5Csqrt%7B3%7D%2C%206%29%20%5C%2C%5Bkm%5D)
The magnitude of the resultant is found by Pythagorean theorem:

And the bearing is determined by the following <em>inverse</em> trigonometric relationship:
(3)
If we know that
and
, then the magnitude and the bearing of the resultant is:




The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.
To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/21925479
Answer: £5.39
Step-by-step explanation:
500g strawberries = 4.10
100 g = 0.82
300g = 2.46
400g raspberries = 7.46 - 2.46 = 5.00
100g = 1.25
300g = 3.75
200g strawberries = 0.82 * 2 = 1.64
3.75 + 1.64 = 5.39
I think it'd be better if you gave us some sort of diagram with it?
3 = 2 by z property
Step-by-step explanation:
Congruence criteria for triangles
If two sides and the angle between them in one triangle have the same measures as two sides and the angle between them in another triangle, then the triangles are congruent.
Please mark as brainliest
The answer is either Dr Tanenbaum or Dr hong.<span />