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bagirrra123 [75]
2 years ago
11

How many times larger is the diameter than the radius of a circle?

Mathematics
2 answers:
UNO [17]2 years ago
6 0
  • The diameter is always twice the radius, so either form of the equation works.

<h2>HOPE IT HELPS❤</h2>
Effectus [21]2 years ago
4 0

Answer:

The diameter is always twice the radius.

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Mon wants to make 5 lbs of the sugar syrup. How much water and how much sugar does he need…
nata0808 [166]
Whatever% of anything, is just (whatever/100) * anything.

the syrup is going to be 5lbs total, that includes the sugar in it as well as the water mix.

keeping in mind that the syrup will be a 1.5% syrup, namely 1.5% of it will be sugar, the rest just water then, how much is 1.5% of 5?

well, is just(1.5/100) * 5 or 0.075, namely lbs.

so, 0.075 lbs will be sugar and the rest water, the rest will be 5 - 0.075, or 4.925 lbs.
7 0
3 years ago
Easy geometry question about rhombus/measures :))
OLEGan [10]

Answer:

∠1 = 51

∠2= 51

∠3= 39

∠4= 51

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2 years ago
Y=109x <br>y=79x+2506<br> can some one solve both equations and a graph would be helpful plz
Amiraneli [1.4K]

Answer:

x ≈ 83.533

y = 9105.13

Step-by-step explanation:

Step 1: Substitution

109x = 79x + 2506

30x = 2506

x = 83.533

Step 2: Plug <em>x</em> in

y = 109(83.533)

y = 9105.13

Graphically:

5 0
3 years ago
Joseph has a credit card with his bank but he must pay off completely each month for each day that His payment is late the bank
CaHeK987 [17]

Answer:

3%

Step-by-step explanation:

First find the difference between the total payment and what the payment would have been prior to to the 20 days late fee. Divide that number by the amount of days overdue (20) to find the cost of each day overdue. Divide that number of what each day overdue is by the cost of the bill prior to overdue fees. Move the decimal two places to the right.

5 0
3 years ago
Find two positive numbers satisfying the given requirements.
Umnica [9.8K]

Answer:

8 and 19

Step-by-step explanation:

To some this, let's first list all the factors of 152. They are;

1, 2, 4, 8, 19, 38, 76, 152.

Now, let's arrange them to reflect being multiplied to get 152.

Thus;

1 × 152 = 152

2 × 76 = 152

4 × 38 = 152

8 × 19 = 152

Also, let's do the same for their sum;

1 + 152 = 153

2 + 76 = 78

4 + 38 = 42

8 + 19 = 27

Looking at the figures above, the ones that their product is 152 but have the least sum are 8 and 19

8 0
2 years ago
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