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Yuki888 [10]
3 years ago
6

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Mathematics
1 answer:
MaRussiya [10]3 years ago
5 0

Answer:

(11, -13)

Step-by-step explanation:

A is at (3, -5) and B is at (13, -15)

A point that is ⅘ of the way from A to B also divides the differences of the x-and y-coordinates in the same ratio.

For the x-coordinate,

x₂ - x₁ = 13 - 3 = 10

⅘ × 10 = 8  

 3 + 8 = 11

The x-coordinate of the point is x = 11.

For the y-coordinate,

y₂ - y₁ = -15 - (-5) = -15 + 5 = -10

⅘ × (-10) = -8

-5 + (-8)  = -13

The y-coordinate of the point is at y = -13.

The coordinates of the point are then (11, -13).

The diagram below shows the point ⅘ of the way from A to B.

 

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I need to show work and Idk how for 2 or 3. The -5,-2 and 8,3 is the answers just need work shown thanks
prisoha [69]
#2
2x - 4y = -2
2x + 3y = -16
------------------subtract
-7y = 14
y = 14/-7
y = -2

2x - 4y = -2
2x - 4(-2) = -2
2x + 8 = -2
2x = -2 -8
2x = -10
x = -10/2
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answer x = -2 and y = -5

check:

2(-5)- 4(-2) = -2
-10 +8 = -2
-2 = -2.....true

2x + 3y = -16
2(-5)+3(-2) = -16
-10 + (-6) = -16
-16 = -16...true


3 0
3 years ago
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3 years ago
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What is the quotient of a number and three is negative four
Alecsey [184]

Answer:

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Step-by-step explanation:

7-3=4

3 0
3 years ago
The equation 2x^2 – 8x = 5 is rewritten in the form of 2(x – p)^2 + q = 0. what is the value of q?
QveST [7]

Answer:

q = -13

Step-by-step explanation:

The given equation is:

2x^{2}-8x=5

Taking 2 as common from left hand side, we get:

2(x^{2}-4x)=5\\\\2[x^{2} - 2(x)(2)]=5

The square of difference is written as:

(a-b)^{2}=a^2 - 2ab + b^{2}                            Equation 1

If we compare the given equation from previous step to formula in Equation 1, we note that we have square of first term(x), twice the product of 1st term(x) and second term(2) and the square of second term(2) is missing. So in order to complete the square we need to add and subtract square of 2 to right hand side. i.e.

2[x^{2}-2(x)(2)+(2)^2-(2)^{2}]=5\\\\ 2[x^{2}-2(x)(2)+(2)^2]-2(2)^{2}=5\\\\ 2(x-2)^{2}-2(4)=5\\\\ 2(x-2)^2-8=5\\\\ 2(x-2)^{2}-8-5=0\\\\ 2(x-2)^{2}-13=0

Comparing the above equation with the given equation:

2(x-p)^{2}+q=0, we can say:

p = 2 and q= -13

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