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icang [17]
2 years ago
5

Y intersect of a graph showing the points A(0,-6) and B (7,8)

Mathematics
2 answers:
Step2247 [10]2 years ago
4 0

Answer:

  • A(0, - 6) is the y-intercept

Step-by-step explanation:

The y-intercept is the point where the graph intersects the y-axis.

It is a point with zero x-coordinate.

As we see the point A has x = 0, y = - 6 coordinates, it is therefore a y-intercept.

Vikki [24]2 years ago
3 0

Answer:

y = 2x - 6

Step-by-step explanation:

given : A(0,-6) and B (7,8)

gradient = 8 - -6 / 7 -0

              = 14/7

              = 2

line : y - - 6 = 2 ( x - 0 )

      : y + 6 = 2x

      : y = 2x - 6

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Let A be a 3 by 6 , B be a 6 by 7 and C be a 7 by 3 matrix. Determine the size of the following matrices (if they do not exist,
kozerog [31]

Answer:

a. AB: 3 by 7

b. BA: N by N

c. A^TB: N by N

d. BC: 6 by 3

Step-by-step explanation:

Given

A =3\ by\ 6

B =6\ by\ 7

C =7\ by\ 3

Required

The dimension of the following matrices

As a general rule:

For A * B to be successful, the columns in a must equal the rows in B

Using this rule, we have:

A_{m*n} * B_{n * p} = AB_{m*p}

So:

(a)\ AB

A_{3*6} * B_{6*7} \to AB_{3 * 7}

(b)\ BA

B_{6*7} * A_{3*6} \to AB_{N * N}

The column numbers of B does not equal the row numbers of A.

Hence, BA does not exist

(c)\ A^TB

A^T implies that:

If A =3\ by\ 6, then

A^T = 6\ by\ 3

So:

A^T_{6*3} * B_{6,7} \to A^TB_{N*N}

The column numbers of A^T does not equal the row numbers of B.

Hence, A^TB does not exist

(d)\ BC

B_{6*7} * C_{7*3} \to BC_{6,3}

6 0
3 years ago
Help would be appreciated, thanks
torisob [31]

Answer:

-8

Step-by-step explanation:

the pattern is times 4

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3 0
2 years ago
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How do I change my username because it is stuck on the email. I will give Brainliest.
Aleonysh [2.5K]

Answer:

Stated below:

Step-by-step explanation:

You can't change your Brainly username unless you want to make a new account.  

6 0
3 years ago
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Image attachment below, Algebra 1 stuff
chubhunter [2.5K]
I know you didn't want an explanation, but I'll give you one anyway.
So, for a function, when you have f(5) = , then you'll put that 5 in for all of the x's in the function. 

The first batch of problems gave you the equation f(x) = \frac{x}{2} + 3. Now, plug in the numbers given for s and solve.

1. f(5) = <span>\frac{x}{2} + 3   Plug in 5 for x
</span>         = \frac{5}{2} + 3   Make three into a fraction over 2
         = \frac{5}{2} + <span>\frac{6}{2}   Add
         = </span><span><span>\frac{11}{2}

</span>2. f(-4) = </span><span>\frac{x}{2} + 3   Plug in -4 for x
           = </span><span>\frac{-4}{2} + 3   Divide -4 by 2
           = -2 + 3   Add
           = 1

For the next set, you have g(x) = x</span>² + 1.

3. Let's split this up. Solve the first equation, then the second, and then put         the answers together to solve it.

g(4) = x² + 1   Plug in 4 for x
       = 4² + 1   Square
       = 16 + 1   Add
       = 17

g(3) = x² + 1   Plug in 3 for x
       = 3² + 1   Square
       = 9 + 1   Add
       = 10

Now, put the two together.

g(4) + g(3) =    Substitute in the answers you just got.
      17 + 10 =    Add
                  = 27         

4. g(-1) = x² + 1      Substitute in -1 for x
            = (-1)² + 1   Square
            = 1 + 1        Add
            = 2

5. g(-6) = x² + 1       Plug in -6 for x
             = (-6)² + 1   Square
             = 36 + 1      Add
             = 37

For the last set, we have h(x) = x² + 7 and k(x) = 4x - 5. We'll have to pay close attention to the starting variables here.

6. h(-6) = x² + 7       Plug in -6 for x
             = (-6)² + 7   Square
             = 36 + 7      Add
             = 43

k(4) = 4x - 5     Plug in 4 for x
       = 4(4) - 5   Multiply
       = 16 - 5      Subtract
       = 11

Put the two answers into the final equation.

h(-6) + k(4) =    Substitute in the answers you got
       43 + 11 =    Add
                   = 54

7. k(10) = 4x - 5       Plug in 10 for x
            = 4(10) - 5   Multiply
            = 40 - 5      Subtract
            = 35

h(2) = x² + 7   Plug in 2 for x
       = 2² + 7   Square
       = 4 + 7     Add
       = 11

Now, put those into the equation.

k(10) - h(2) =    Plug in the answers you got
       35 - 11 =    Subtract
                  = 24

8. For this one, it wants you to add h(x) and k(x). We don't need to plug anything into the equations this time because they're both already solved for x! So, you can just set this up like a standard find-x equation.

(x² + 7) + (4x - 5) =
    x² + 7 + 4x - 5 =   Combine like terms (7 and -5)
         x² + 2 + 4x =    Reorder so the variables come first
                            = x² + 4x + 2

  
4 0
3 years ago
Read 2 more answers
Let C be between D and E. Solve for x <br> DC = 5x + 8<br> CE = 3x + 5<br> DE = 61
morpeh [17]
DE/2 = 30.5
CE=30.5
DC=30.5

3x + 5 = 30.5
3x = 30.5 - 5
3x = 25.5
25.5/3 =8.5
x=8.5
8 0
3 years ago
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