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icang [17]
2 years ago
5

Y intersect of a graph showing the points A(0,-6) and B (7,8)

Mathematics
2 answers:
Step2247 [10]2 years ago
4 0

Answer:

  • A(0, - 6) is the y-intercept

Step-by-step explanation:

The y-intercept is the point where the graph intersects the y-axis.

It is a point with zero x-coordinate.

As we see the point A has x = 0, y = - 6 coordinates, it is therefore a y-intercept.

Vikki [24]2 years ago
3 0

Answer:

y = 2x - 6

Step-by-step explanation:

given : A(0,-6) and B (7,8)

gradient = 8 - -6 / 7 -0

              = 14/7

              = 2

line : y - - 6 = 2 ( x - 0 )

      : y + 6 = 2x

      : y = 2x - 6

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Anvisha [2.4K]
Y=6
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3 0
3 years ago
Translate to an equation and solve: The sum of two-fifths and f is one-half.<br> Provide<br> f=
SCORPION-xisa [38]

Answer:

9/10

1/2+2/5

Since these fractions have different denominators, we need to find the least common multiple of the denominators.The least common multiple of 2 and 5 is 10, so we need to multiply to make each of the denominators = 10

1/2 ∗ 5/5 = 5/10

5/2∗ 2/2= 4/10

Since these fractions have the same denominator, we can just add the numerators

5/10+ 4/10 = 9/10

3 0
2 years ago
Heyyyyy pleasse help me please please and thank you
dimulka [17.4K]

Answer:

x ≈ 33.1°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = \frac{opposite}{adjacent} = \frac{125}{192} , then

x = tan^{-1} ( \frac{125}{192} ) ≈ 33.1° ( to the nearest tenth )

7 0
2 years ago
I don't understand number 8
Norma-Jean [14]
Let's try plugging in some negative numbers. Let's do x=-1. 5+-1=4. So we know that if we put in a negative number for x, then n will be positive. But what if we do a number greater than -5, because 5+-5=0. So let's try x=-6. So 5+(-6)=-1. Hmm. So here it is. We know that any number under -5 will be positive and any number above -5 will be negative.
8 0
3 years ago
Help geometry what I m jlf <br> Picture provided
Zolol [24]

Answer:

\angle\,JLF = 114^o  which agrees with option"B" of the possible answers listed

Step-by-step explanation:

Notice that in order to solve this problem  (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from 180^o, since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as 90^o and 138^o. (see attached image)

We put our efforts into solving the right angle triangle denoted with green borders.

Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by : 360^o-90^o-138^o=132^o

Therefore, the two equal acute angles in the triangle JOH should add to:

180^o-132^o=48^o resulting then in each small acute angle of measure 24^o.

Now referring to the green sided right angle triangle we can find find angle JLG, using: 180^o-24^o-90^o=66^o

Finally, the requested measure of angle JLF is obtained via: 180^o-66^o=114^o

4 0
3 years ago
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