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Eva8 [605]
3 years ago
5

The rabbit population of Springfield, Ohio was 144,000 in 2016. It is expected to decrease by about 7.2% per year. Write an expo

nential decay function, P(t), and use it to approximate the population in 2036.
Mathematics
1 answer:
xeze [42]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

In 2036 there will be a population of 32309 rabbits.

<h2>Why?</h2>

We can calculate the exponential decay using the following function:

P(t)=StartAmount*(1-\frac{percent}{100})^{t}

Where,

Start Amount, is the starting value or amount.

Percent, is the decay rate.

t, is the time elapsed.

We are given:

StartAmount=144,000\\x=7.2(percent)\\t=2036-2016=20years

Now, substituting it into the equation, we have:

P(t)=StartAmount(1-\frac{percent}{100})^{t}

P(t)=144000*(1-\frac{7.2}{100})^{20}

P(t)=144000*(1-0.072)^{20}

P(t)=144000*(0.928)^{20}

P(t)=144000*(0.928)^{20}

P(t)=144000*0.861=32308.888=32309

Hence, we have that in 2036 the population of rabbis will be 32309 rabbits.

Have a nice day!

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The value of x is 1.66

Step-by-step explanation:

Let use revise the rules of exponential and logarithmic equations

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Use the rules above to solve the problem

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6 0
4 years ago
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klio [65]
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3 years ago
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The following table shows the number of hours some high school students in two states spend surfing the Internet each week:
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1st data set:

Minimum: 34
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3rd quartile: 37
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Second data set:
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1st quartile: 23
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3rd quartile: 38
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Graph it based on the values of the 1st and 3rd quartile. If they are both the same number away from the mean then they are symmetrical. Otherwise they are not. In this case, the first one is similar and the second one is not.

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7 0
4 years ago
For the graph, what is a reasonable constraint so that the function is at least 300?
blsea [12.9K]

Answer:

C) 0 ≤ x ≤ 25

Step-by-step explanation:

We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300

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Refer the graph

At x = 0

f(x)=300

On increasing the value of x , f(x) increases but at x = 12 it starts decreasing

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So, Option A is wrong

B)−5 ≤ x ≤ 30

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So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25

D)All real numbers

At x = 30

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